Triangle calculator

Please enter what you know about the triangle:
Symbols definition of ABC triangle

You have entered height ha, angle α and angle β.

Right isosceles triangle.

Sides: a = 110   b = 77.78217459305   c = 77.78217459305

Area: T = 3025
Perimeter: p = 265.5633491861
Semiperimeter: s = 132.782174593

Angle ∠ A = α = 90° = 1.57107963268 rad
Angle ∠ B = β = 45° = 0.78553981634 rad
Angle ∠ C = γ = 45° = 0.78553981634 rad

Height: ha = 55
Height: hb = 77.78217459305
Height: hc = 77.78217459305

Median: ma = 55
Median: mb = 86.96326356546
Median: mc = 86.96326356546

Inradius: r = 22.78217459305
Circumradius: R = 55

Vertex coordinates: A[77.78217459305; 0] B[0; 0] C[77.78217459305; 77.78217459305]
Centroid: CG[51.8544497287; 25.92772486435]
Coordinates of the circumscribed circle: U[38.89108729653; 38.89108729653]
Coordinates of the inscribed circle: I[55; 22.78217459305]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 90° = 1.57107963268 rad
∠ B' = β' = 135° = 0.78553981634 rad
∠ C' = γ' = 135° = 0.78553981634 rad

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How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a = 110 ; ; b = 77.78 ; ; c = 77.78 ; ;

1. The triangle circumference is the sum of the lengths of its three sides

p = a+b+c = 110+77.78+77.78 = 265.56 ; ;

2. Semiperimeter of the triangle

s = fraction{ o }{ 2 } = fraction{ 265.56 }{ 2 } = 132.78 ; ;

3. The triangle area using Heron's formula

T = sqrt{ s(s-a)(s-b)(s-c) } ; ; T = sqrt{ 132.78 * (132.78-110)(132.78-77.78)(132.78-77.78) } ; ; T = sqrt{ 9150625 } = 3025 ; ;

4. Calculate the heights of the triangle from its area.

T = fraction{ a h _a }{ 2 } ; ; h _a = fraction{ 2 T }{ a } = fraction{ 2 * 3025 }{ 110 } = 55 ; ; h _b = fraction{ 2 T }{ b } = fraction{ 2 * 3025 }{ 77.78 } = 77.78 ; ; h _c = fraction{ 2 T }{ c } = fraction{ 2 * 3025 }{ 77.78 } = 77.78 ; ;

5. Calculation of the inner angles of the triangle using a Law of Cosines

a**2 = b**2+c**2 - 2bc cos( alpha ) ; ; alpha = arccos( fraction{ a**2-b**2-c**2 }{ 2bc } ) = arccos( fraction{ 110**2-77.78**2-77.78**2 }{ 2 * 77.78 * 77.78 } ) = 90° ; ; beta = arccos( fraction{ b**2-a**2-c**2 }{ 2ac } ) = arccos( fraction{ 77.78**2-110**2-77.78**2 }{ 2 * 110 * 77.78 } ) = 45° ; ; gamma = arccos( fraction{ c**2-a**2-b**2 }{ 2ba } ) = arccos( fraction{ 77.78**2-110**2-77.78**2 }{ 2 * 77.78 * 110 } ) = 45° ; ;

6. Inradius

T = rs ; ; r = fraction{ T }{ s } = fraction{ 3025 }{ 132.78 } = 22.78 ; ;

7. Circumradius

R = fraction{ a }{ 2 * sin( alpha ) } = fraction{ 110 }{ 2 * sin 90° } = 55 ; ;




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