Triangle calculator

Please enter what you know about the triangle:
Symbols definition of ABC triangle

You have entered side b, c and angle α.

Right scalene triangle.

Sides: a = 145.7899471499   b = 111.1   c = 94.4

Area: T = 5243.92
Perimeter: p = 351.2899471499
Semiperimeter: s = 175.645473575

Angle ∠ A = α = 90° = 1.57107963268 rad
Angle ∠ B = β = 49.64659439969° = 49°38'45″ = 0.8666485183 rad
Angle ∠ C = γ = 40.35440560031° = 40°21'15″ = 0.70443111438 rad

Height: ha = 71.93882537858
Height: hb = 94.4
Height: hc = 111.1

Median: ma = 72.89547357496
Median: mb = 109.5321559379
Median: mc = 120.7110604339

Inradius: r = 29.85552642504
Circumradius: R = 72.89547357496

Vertex coordinates: A[94.4; 0] B[0; 0] C[94.4; 111.1]
Centroid: CG[62.93333333333; 37.03333333333]
Coordinates of the circumscribed circle: U[47.2; 55.55]
Coordinates of the inscribed circle: I[64.54547357496; 29.85552642504]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 90° = 1.57107963268 rad
∠ B' = β' = 130.3544056003° = 130°21'15″ = 0.8666485183 rad
∠ C' = γ' = 139.6465943997° = 139°38'45″ = 0.70443111438 rad

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How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a = 145.79 ; ; b = 111.1 ; ; c = 94.4 ; ;

1. The triangle circumference is the sum of the lengths of its three sides

p = a+b+c = 145.79+111.1+94.4 = 351.29 ; ;

2. Semiperimeter of the triangle

s = fraction{ o }{ 2 } = fraction{ 351.29 }{ 2 } = 175.64 ; ;

3. The triangle area using Heron's formula

T = sqrt{ s(s-a)(s-b)(s-c) } ; ; T = sqrt{ 175.64 * (175.64-145.79)(175.64-111.1)(175.64-94.4) } ; ; T = sqrt{ 27498696.97 } = 5243.92 ; ;

4. Calculate the heights of the triangle from its area.

T = fraction{ a h _a }{ 2 } ; ; h _a = fraction{ 2 T }{ a } = fraction{ 2 * 5243.92 }{ 145.79 } = 71.94 ; ; h _b = fraction{ 2 T }{ b } = fraction{ 2 * 5243.92 }{ 111.1 } = 94.4 ; ; h _c = fraction{ 2 T }{ c } = fraction{ 2 * 5243.92 }{ 94.4 } = 111.1 ; ;

5. Calculation of the inner angles of the triangle using a Law of Cosines

a**2 = b**2+c**2 - 2bc cos( alpha ) ; ; alpha = arccos( fraction{ a**2-b**2-c**2 }{ 2bc } ) = arccos( fraction{ 145.79**2-111.1**2-94.4**2 }{ 2 * 111.1 * 94.4 } ) = 90° ; ; beta = arccos( fraction{ b**2-a**2-c**2 }{ 2ac } ) = arccos( fraction{ 111.1**2-145.79**2-94.4**2 }{ 2 * 145.79 * 94.4 } ) = 49° 38'45" ; ; gamma = arccos( fraction{ c**2-a**2-b**2 }{ 2ba } ) = arccos( fraction{ 94.4**2-145.79**2-111.1**2 }{ 2 * 111.1 * 145.79 } ) = 40° 21'15" ; ;

6. Inradius

T = rs ; ; r = fraction{ T }{ s } = fraction{ 5243.92 }{ 175.64 } = 29.86 ; ;

7. Circumradius

R = fraction{ a }{ 2 * sin( alpha ) } = fraction{ 145.79 }{ 2 * sin 90° } = 72.89 ; ;




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