Triangle calculator

Please enter what you know about the triangle:
Symbols definition of ABC triangle

You have entered side a, angle β and angle γ.

Right scalene triangle.

Sides: a = 60   b = 34.64110161514   c = 69.28220323028

Area: T = 1039.233048454
Perimeter: p = 163.9233048454
Semiperimeter: s = 81.96215242271

Angle ∠ A = α = 60° = 1.04771975512 rad
Angle ∠ B = β = 30° = 0.52435987756 rad
Angle ∠ C = γ = 90° = 1.57107963268 rad

Height: ha = 34.64110161514
Height: hb = 60
Height: hc = 30

Median: ma = 45.82657569496
Median: mb = 62.4549979984
Median: mc = 34.64110161514

Inradius: r = 12.67994919243
Circumradius: R = 34.64110161514

Vertex coordinates: A[69.28220323028; 0] B[0; 0] C[51.96215242271; 30]
Centroid: CG[40.41545188433; 10]
Coordinates of the circumscribed circle: U[34.64110161514; -0]
Coordinates of the inscribed circle: I[47.32105080757; 12.67994919243]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 120° = 1.04771975512 rad
∠ B' = β' = 150° = 0.52435987756 rad
∠ C' = γ' = 90° = 1.57107963268 rad

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How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a = 60 ; ; b = 34.64 ; ; c = 69.28 ; ;

1. The triangle circumference is the sum of the lengths of its three sides

p = a+b+c = 60+34.64+69.28 = 163.92 ; ;

2. Semiperimeter of the triangle

s = fraction{ o }{ 2 } = fraction{ 163.92 }{ 2 } = 81.96 ; ;

3. The triangle area using Heron's formula

T = sqrt{ s(s-a)(s-b)(s-c) } ; ; T = sqrt{ 81.96 * (81.96-60)(81.96-34.64)(81.96-69.28) } ; ; T = sqrt{ 1080000 } = 1039.23 ; ;

4. Calculate the heights of the triangle from its area.

T = fraction{ a h _a }{ 2 } ; ; h _a = fraction{ 2 T }{ a } = fraction{ 2 * 1039.23 }{ 60 } = 34.64 ; ; h _b = fraction{ 2 T }{ b } = fraction{ 2 * 1039.23 }{ 34.64 } = 60 ; ; h _c = fraction{ 2 T }{ c } = fraction{ 2 * 1039.23 }{ 69.28 } = 30 ; ;

5. Calculation of the inner angles of the triangle using a Law of Cosines

a**2 = b**2+c**2 - 2bc cos( alpha ) ; ; alpha = arccos( fraction{ a**2-b**2-c**2 }{ 2bc } ) = arccos( fraction{ 60**2-34.64**2-69.28**2 }{ 2 * 34.64 * 69.28 } ) = 60° ; ; beta = arccos( fraction{ b**2-a**2-c**2 }{ 2ac } ) = arccos( fraction{ 34.64**2-60**2-69.28**2 }{ 2 * 60 * 69.28 } ) = 30° ; ; gamma = arccos( fraction{ c**2-a**2-b**2 }{ 2ba } ) = arccos( fraction{ 69.28**2-60**2-34.64**2 }{ 2 * 34.64 * 60 } ) = 90° ; ;

6. Inradius

T = rs ; ; r = fraction{ T }{ s } = fraction{ 1039.23 }{ 81.96 } = 12.68 ; ;

7. Circumradius

R = fraction{ a }{ 2 * sin( alpha ) } = fraction{ 60 }{ 2 * sin 60° } = 34.64 ; ;




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