Triangle calculator

Please enter what you know about the triangle:
Symbols definition of ABC triangle

You have entered side b, c and height hc.

Acute scalene triangle.

Sides: a = 52.15440046522   b = 48   c = 60

Area: T = 1200
Perimeter: p = 160.1544004652
Semiperimeter: s = 80.07770023261

Angle ∠ A = α = 56.44326902381° = 56°26'34″ = 0.98551107833 rad
Angle ∠ B = β = 50.08216182447° = 50°4'54″ = 0.87440891331 rad
Angle ∠ C = γ = 73.47656915172° = 73°28'32″ = 1.28223927372 rad

Height: ha = 46.01875592652
Height: hb = 50
Height: hc = 40

Median: ma = 47.66553957257
Median: mb = 50.83332578203
Median: mc = 40.15499701199

Inradius: r = 14.98655759474
Circumradius: R = 31.29224027913

Vertex coordinates: A[60; 0] B[0; 0] C[33.46770016772; 40]
Centroid: CG[31.15656672257; 13.33333333333]
Coordinates of the circumscribed circle: U[30; 8.99002512579]
Coordinates of the inscribed circle: I[32.07770023261; 14.98655759474]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 123.5577309762° = 123°33'26″ = 0.98551107833 rad
∠ B' = β' = 129.9188381755° = 129°55'6″ = 0.87440891331 rad
∠ C' = γ' = 106.5244308483° = 106°31'28″ = 1.28223927372 rad

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How did we calculate this triangle?

1. Input data entered: side b, c and height hc.

b = 48 ; ; c = 60 ; ; hc = 40 ; ;

2. Calculation of the third side a of the triangle using a Law of Cosines

a**2 = b**2+c**2 - 2bc cos alpha ; ; a = sqrt{ b**2+c**2 - 2bc cos alpha } ; ; a = sqrt{ 48**2+60**2 - 2 * 48 * 60 * cos(56° 26'34") } ; ; a = 52.15 ; ;


Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a = 52.15 ; ; b = 48 ; ; c = 60 ; ;

3. The triangle circumference is the sum of the lengths of its three sides

p = a+b+c = 52.15+48+60 = 160.15 ; ;

4. Semiperimeter of the triangle

s = fraction{ o }{ 2 } = fraction{ 160.15 }{ 2 } = 80.08 ; ;

5. The triangle area using Heron's formula

T = sqrt{ s(s-a)(s-b)(s-c) } ; ; T = sqrt{ 80.08 * (80.08-52.15)(80.08-48)(80.08-60) } ; ; T = sqrt{ 1440000 } = 1200 ; ;

6. Calculate the heights of the triangle from its area.

T = fraction{ a h _a }{ 2 } ; ; h _a = fraction{ 2 T }{ a } = fraction{ 2 * 1200 }{ 52.15 } = 46.02 ; ; h _b = fraction{ 2 T }{ b } = fraction{ 2 * 1200 }{ 48 } = 50 ; ; h _c = fraction{ 2 T }{ c } = fraction{ 2 * 1200 }{ 60 } = 40 ; ;

7. Calculation of the inner angles of the triangle using a Law of Cosines

a**2 = b**2+c**2 - 2bc cos( alpha ) ; ; alpha = arccos( fraction{ a**2-b**2-c**2 }{ 2bc } ) = arccos( fraction{ 52.15**2-48**2-60**2 }{ 2 * 48 * 60 } ) = 56° 26'34" ; ; beta = arccos( fraction{ b**2-a**2-c**2 }{ 2ac } ) = arccos( fraction{ 48**2-52.15**2-60**2 }{ 2 * 52.15 * 60 } ) = 50° 4'54" ; ; gamma = arccos( fraction{ c**2-a**2-b**2 }{ 2ba } ) = arccos( fraction{ 60**2-52.15**2-48**2 }{ 2 * 48 * 52.15 } ) = 73° 28'32" ; ;

8. Inradius

T = rs ; ; r = fraction{ T }{ s } = fraction{ 1200 }{ 80.08 } = 14.99 ; ;

9. Circumradius

R = fraction{ a }{ 2 * sin( alpha ) } = fraction{ 52.15 }{ 2 * sin 56° 26'34" } = 31.29 ; ;




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