9 10 16 triangle

Obtuse scalene triangle.

Sides: a = 9   b = 10   c = 16

Area: T = 40.90876704299
Perimeter: p = 35
Semiperimeter: s = 17.5

Angle ∠ A = α = 30.75435198081° = 30°45'13″ = 0.53767501772 rad
Angle ∠ B = β = 34.62221618397° = 34°37'20″ = 0.60442707183 rad
Angle ∠ C = γ = 114.6244318352° = 114°37'28″ = 2.00105717581 rad

Height: ha = 9.09105934289
Height: hb = 8.1821534086
Height: hc = 5.11334588037

Median: ma = 12.56598566871
Median: mb = 11.97991485507
Median: mc = 5.14878150705

Vertex coordinates: A[16; 0] B[0; 0] C[7.406625; 5.11334588037]
Centroid: CG[7.80220833333; 1.70444862679]
Coordinates of the circumscribed circle: U[8; -3.66767939881]
Coordinates of the inscribed circle: I[7.5; 2.33875811674]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 149.2466480192° = 149°14'47″ = 0.53767501772 rad
∠ B' = β' = 145.378783816° = 145°22'40″ = 0.60442707183 rad
∠ C' = γ' = 65.37656816478° = 65°22'32″ = 2.00105717581 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    