6 27 28 triangle

Obtuse scalene triangle.

Sides: a = 6   b = 27   c = 28

Area: T = 80.8610605365
Perimeter: p = 61
Semiperimeter: s = 30.5

Angle ∠ A = α = 12.35219946365° = 12°21'7″ = 0.21655829756 rad
Angle ∠ B = β = 74.2866138952° = 74°17'10″ = 1.29765377133 rad
Angle ∠ C = γ = 93.36218664115° = 93°21'43″ = 1.62994719647 rad

Height: ha = 26.95435351217
Height: hb = 5.99896744715
Height: hc = 5.77657575261

Median: ma = 27.3440446229
Median: mb = 15.09113882728
Median: mc = 13.65765002837

Vertex coordinates: A[28; 0] B[0; 0] C[1.625; 5.77657575261]
Centroid: CG[9.875; 1.92552525087]
Coordinates of the circumscribed circle: U[14; -0.82224029452]
Coordinates of the inscribed circle: I[3.5; 2.6511167389]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 167.6488005363° = 167°38'53″ = 0.21655829756 rad
∠ B' = β' = 105.7143861048° = 105°42'50″ = 1.29765377133 rad
∠ C' = γ' = 86.63881335885° = 86°38'17″ = 1.62994719647 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    