6 23 28 triangle

Obtuse scalene triangle.

Sides: a = 6   b = 23   c = 28

Area: T = 41.99333030375
Perimeter: p = 57
Semiperimeter: s = 28.5

Angle ∠ A = α = 7.49435155488° = 7°29'37″ = 0.13107865189 rad
Angle ∠ B = β = 29.99547255274° = 29°59'41″ = 0.52435067187 rad
Angle ∠ C = γ = 142.5121758924° = 142°30'42″ = 2.4877299416 rad

Height: ha = 13.99877676792
Height: hb = 3.65215915685
Height: hc = 32.9995216455

Median: ma = 25.44660213
Median: mb = 16.66658333125
Median: mc = 9.30105376189

Vertex coordinates: A[28; 0] B[0; 0] C[5.19664285714; 32.9995216455]
Centroid: CG[11.06554761905; 10.9998405485]
Coordinates of the circumscribed circle: U[14; -18.25329104537]
Coordinates of the inscribed circle: I[5.5; 1.47334492294]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 172.5066484451° = 172°30'23″ = 0.13107865189 rad
∠ B' = β' = 150.0055274473° = 150°19″ = 0.52435067187 rad
∠ C' = γ' = 37.48882410762° = 37°29'18″ = 2.4877299416 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    