6 23 23 triangle

Acute isosceles triangle.

Sides: a = 6   b = 23   c = 23

Area: T = 68.41105255059
Perimeter: p = 52
Semiperimeter: s = 26

Angle ∠ A = α = 14.98994349079° = 14°59'22″ = 0.26216149922 rad
Angle ∠ B = β = 82.50552825461° = 82°30'19″ = 1.44399888307 rad
Angle ∠ C = γ = 82.50552825461° = 82°30'19″ = 1.44399888307 rad

Height: ha = 22.8043508502
Height: hb = 5.94987413483
Height: hc = 5.94987413483

Median: ma = 22.8043508502
Median: mb = 12.25876506721
Median: mc = 12.25876506721

Vertex coordinates: A[23; 0] B[0; 0] C[0.78326086957; 5.94987413483]
Centroid: CG[7.92875362319; 1.98329137828]
Coordinates of the circumscribed circle: U[11.5; 1.51329250833]
Coordinates of the inscribed circle: I[3; 2.63111740579]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 165.0110565092° = 165°38″ = 0.26216149922 rad
∠ B' = β' = 97.49547174539° = 97°29'41″ = 1.44399888307 rad
∠ C' = γ' = 97.49547174539° = 97°29'41″ = 1.44399888307 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    