6 15 19 triangle

Obtuse scalene triangle.

Sides: a = 6   b = 15   c = 19

Area: T = 37.41765738677
Perimeter: p = 40
Semiperimeter: s = 20

Angle ∠ A = α = 15.22327570342° = 15°13'22″ = 0.26656872315 rad
Angle ∠ B = β = 41.02882543699° = 41°1'42″ = 0.71660781251 rad
Angle ∠ C = γ = 123.7498988596° = 123°44'56″ = 2.1659827297 rad

Height: ha = 12.47221912892
Height: hb = 4.98988765157
Height: hc = 3.93985867229

Median: ma = 16.85222995464
Median: mb = 11.92768604419
Median: mc = 6.34442887702

Vertex coordinates: A[19; 0] B[0; 0] C[4.52663157895; 3.93985867229]
Centroid: CG[7.84221052632; 1.3132862241]
Coordinates of the circumscribed circle: U[9.5; -6.34774544954]
Coordinates of the inscribed circle: I[5; 1.87108286934]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 164.7777242966° = 164°46'38″ = 0.26656872315 rad
∠ B' = β' = 138.972174563° = 138°58'18″ = 0.71660781251 rad
∠ C' = γ' = 56.25110114041° = 56°15'4″ = 2.1659827297 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    