23 30 30 triangle

Acute isosceles triangle.

Sides: a = 23   b = 30   c = 30

Area: T = 318.6455473057
Perimeter: p = 83
Semiperimeter: s = 41.5

Angle ∠ A = α = 45.0810620927° = 45°4'50″ = 0.7876805264 rad
Angle ∠ B = β = 67.46596895365° = 67°27'35″ = 1.17773936948 rad
Angle ∠ C = γ = 67.46596895365° = 67°27'35″ = 1.17773936948 rad

Height: ha = 27.7088302005
Height: hb = 21.24330315372
Height: hc = 21.24330315372

Median: ma = 27.7088302005
Median: mb = 22.12546468898
Median: mc = 22.12546468898

Vertex coordinates: A[30; 0] B[0; 0] C[8.81766666667; 21.24330315372]
Centroid: CG[12.93988888889; 7.08110105124]
Coordinates of the circumscribed circle: U[15; 6.22655709487]
Coordinates of the inscribed circle: I[11.5; 7.67882041701]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 134.9199379073° = 134°55'10″ = 0.7876805264 rad
∠ B' = β' = 112.5440310464° = 112°32'25″ = 1.17773936948 rad
∠ C' = γ' = 112.5440310464° = 112°32'25″ = 1.17773936948 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    