20 29 29 triangle

Acute isosceles triangle.

Sides: a = 20   b = 29   c = 29

Area: T = 272.2133151776
Perimeter: p = 78
Semiperimeter: s = 39

Angle ∠ A = α = 40.34325426929° = 40°20'33″ = 0.70441101986 rad
Angle ∠ B = β = 69.82987286535° = 69°49'43″ = 1.21987412275 rad
Angle ∠ C = γ = 69.82987286535° = 69°49'43″ = 1.21987412275 rad

Height: ha = 27.22113151776
Height: hb = 18.77333208122
Height: hc = 18.77333208122

Median: ma = 27.22113151776
Median: mb = 20.25546291005
Median: mc = 20.25546291005

Vertex coordinates: A[29; 0] B[0; 0] C[6.89765517241; 18.77333208122]
Centroid: CG[11.96655172414; 6.25877736041]
Coordinates of the circumscribed circle: U[14.5; 5.32767080982]
Coordinates of the inscribed circle: I[10; 6.98798244045]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 139.6577457307° = 139°39'27″ = 0.70441101986 rad
∠ B' = β' = 110.1711271346° = 110°10'17″ = 1.21987412275 rad
∠ C' = γ' = 110.1711271346° = 110°10'17″ = 1.21987412275 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    