2 23 23 triangle

Acute isosceles triangle.

Sides: a = 2   b = 23   c = 23

Area: T = 22.97882505862
Perimeter: p = 48
Semiperimeter: s = 24

Angle ∠ A = α = 4.9843812738° = 4°59'2″ = 0.08769839416 rad
Angle ∠ B = β = 87.5088093631° = 87°30'29″ = 1.5277304356 rad
Angle ∠ C = γ = 87.5088093631° = 87°30'29″ = 1.5277304356 rad

Height: ha = 22.97882505862
Height: hb = 1.99881087466
Height: hc = 1.99881087466

Median: ma = 22.97882505862
Median: mb = 11.58766302263
Median: mc = 11.58766302263

Vertex coordinates: A[23; 0] B[0; 0] C[0.08769565217; 1.99881087466]
Centroid: CG[7.69656521739; 0.66660362489]
Coordinates of the circumscribed circle: U[11.5; 0.55004732609]
Coordinates of the inscribed circle: I[1; 0.95774271078]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 175.0166187262° = 175°58″ = 0.08769839416 rad
∠ B' = β' = 92.4921906369° = 92°29'31″ = 1.5277304356 rad
∠ C' = γ' = 92.4921906369° = 92°29'31″ = 1.5277304356 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    