2 10 10 triangle

Acute isosceles triangle.

Sides: a = 2   b = 10   c = 10

Area: T = 9.95498743711
Perimeter: p = 22
Semiperimeter: s = 11

Angle ∠ A = α = 11.47883409545° = 11°28'42″ = 0.22003348423 rad
Angle ∠ B = β = 84.26108295227° = 84°15'39″ = 1.47106289056 rad
Angle ∠ C = γ = 84.26108295227° = 84°15'39″ = 1.47106289056 rad

Height: ha = 9.95498743711
Height: hb = 1.99899748742
Height: hc = 1.99899748742

Median: ma = 9.95498743711
Median: mb = 5.19661524227
Median: mc = 5.19661524227

Vertex coordinates: A[10; 0] B[0; 0] C[0.2; 1.99899748742]
Centroid: CG[3.4; 0.66333249581]
Coordinates of the circumscribed circle: U[5; 0.50325189076]
Coordinates of the inscribed circle: I[1; 0.90545340337]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 168.5221659045° = 168°31'18″ = 0.22003348423 rad
∠ B' = β' = 95.73991704773° = 95°44'21″ = 1.47106289056 rad
∠ C' = γ' = 95.73991704773° = 95°44'21″ = 1.47106289056 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    