16 25 25 triangle

Acute isosceles triangle.

Sides: a = 16   b = 25   c = 25

Area: T = 189.4843508517
Perimeter: p = 66
Semiperimeter: s = 33

Angle ∠ A = α = 37.32658497699° = 37°19'33″ = 0.65114589746 rad
Angle ∠ B = β = 71.33770751151° = 71°20'13″ = 1.24550668395 rad
Angle ∠ C = γ = 71.33770751151° = 71°20'13″ = 1.24550668395 rad

Height: ha = 23.68554385647
Height: hb = 15.15986806814
Height: hc = 15.15986806814

Median: ma = 23.68554385647
Median: mb = 16.86597153001
Median: mc = 16.86597153001

Vertex coordinates: A[25; 0] B[0; 0] C[5.12; 15.15986806814]
Centroid: CG[10.04; 5.05328935605]
Coordinates of the circumscribed circle: U[12.5; 4.22220033092]
Coordinates of the inscribed circle: I[8; 5.74219245005]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 142.674415023° = 142°40'27″ = 0.65114589746 rad
∠ B' = β' = 108.6632924885° = 108°39'47″ = 1.24550668395 rad
∠ C' = γ' = 108.6632924885° = 108°39'47″ = 1.24550668395 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    