14 26 28 triangle

Acute scalene triangle.

Sides: a = 14   b = 26   c = 28

Area: T = 180.665543665
Perimeter: p = 68
Semiperimeter: s = 34

Angle ∠ A = α = 29.75877290681° = 29°45'28″ = 0.51993703502 rad
Angle ∠ B = β = 67.18551127773° = 67°11'6″ = 1.17326014263 rad
Angle ∠ C = γ = 83.05771581546° = 83°3'26″ = 1.45496208771 rad

Height: ha = 25.80993480929
Height: hb = 13.89773412808
Height: hc = 12.90546740464

Median: ma = 26.09659767014
Median: mb = 17.91664728672
Median: mc = 15.49219333848

Vertex coordinates: A[28; 0] B[0; 0] C[5.42985714286; 12.90546740464]
Centroid: CG[11.14328571429; 4.30215580155]
Coordinates of the circumscribed circle: U[14; 1.70548086547]
Coordinates of the inscribed circle: I[8; 5.31436893132]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 150.2422270932° = 150°14'32″ = 0.51993703502 rad
∠ B' = β' = 112.8154887223° = 112°48'54″ = 1.17326014263 rad
∠ C' = γ' = 96.94328418454° = 96°56'34″ = 1.45496208771 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    