# 14 25 25 triangle

### Acute isosceles triangle.

Sides: a = 14   b = 25   c = 25

Area: T = 168
Perimeter: p = 64
Semiperimeter: s = 32

Angle ∠ A = α = 32.52204094166° = 32°31'13″ = 0.56875882184 rad
Angle ∠ B = β = 73.74397952917° = 73°44'23″ = 1.28770022176 rad
Angle ∠ C = γ = 73.74397952917° = 73°44'23″ = 1.28770022176 rad

Height: ha = 24
Height: hb = 13.44
Height: hc = 13.44

Median: ma = 24
Median: mb = 15.94552187191
Median: mc = 15.94552187191

Inradius: r = 5.25
Circumradius: R = 13.02108333333

Vertex coordinates: A[25; 0] B[0; 0] C[3.92; 13.44]
Centroid: CG[9.64; 4.48]
Coordinates of the circumscribed circle: U[12.5; 3.64658333333]
Coordinates of the inscribed circle: I[7; 5.25]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 147.4879590583° = 147°28'47″ = 0.56875882184 rad
∠ B' = β' = 106.2660204708° = 106°15'37″ = 1.28770022176 rad
∠ C' = γ' = 106.2660204708° = 106°15'37″ = 1.28770022176 rad

# How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. ### 1. The triangle circumference is the sum of the lengths of its three sides ### 2. Semiperimeter of the triangle ### 3. The triangle area using Heron's formula ### 4. Calculate the heights of the triangle from its area. ### 5. Calculation of the inner angles of the triangle using a Law of Cosines ### 6. Inradius ### 7. Circumradius ### 8. Calculation of medians #### Look also our friend's collection of math examples and problems:

See more informations about triangles or more information about solving triangles.