14 14 25 triangle

Obtuse isosceles triangle.

Sides: a = 14   b = 14   c = 25

Area: T = 78.81095013307
Perimeter: p = 53
Semiperimeter: s = 26.5

Angle ∠ A = α = 26.76655005768° = 26°45'56″ = 0.4677146111 rad
Angle ∠ B = β = 26.76655005768° = 26°45'56″ = 0.4677146111 rad
Angle ∠ C = γ = 126.4698998846° = 126°28'8″ = 2.20773004316 rad

Height: ha = 11.25985001901
Height: hb = 11.25985001901
Height: hc = 6.30547601065

Median: ma = 19.01331533418
Median: mb = 19.01331533418
Median: mc = 6.30547601065

Vertex coordinates: A[25; 0] B[0; 0] C[12.5; 6.30547601065]
Centroid: CG[12.5; 2.10215867022]
Coordinates of the circumscribed circle: U[12.5; -9.23990509736]
Coordinates of the inscribed circle: I[12.5; 2.97439434464]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 153.2344499423° = 153°14'4″ = 0.4677146111 rad
∠ B' = β' = 153.2344499423° = 153°14'4″ = 0.4677146111 rad
∠ C' = γ' = 53.53110011535° = 53°31'52″ = 2.20773004316 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    