80 60 100 triangle

Right scalene Pythagorean triangle.

Sides: a = 80   b = 60   c = 100

Area: T = 2400
Perimeter: p = 240
Semiperimeter: s = 120

Angle ∠ A = α = 53.13301023542° = 53°7'48″ = 0.9277295218 rad
Angle ∠ B = β = 36.87698976458° = 36°52'12″ = 0.64435011088 rad
Angle ∠ C = γ = 90° = 1.57107963268 rad

Height: ha = 60
Height: hb = 80
Height: hc = 48

Median: ma = 72.11110255093
Median: mb = 85.44400374532
Median: mc = 50

Inradius: r = 20
Circumradius: R = 50

Vertex coordinates: A[100; 0] B[0; 0] C[64; 48]
Centroid: CG[54.66766666667; 16]
Coordinates of the circumscribed circle: U[50; -0]
Coordinates of the inscribed circle: I[60; 20]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 126.8769897646° = 126°52'12″ = 0.9277295218 rad
∠ B' = β' = 143.1330102354° = 143°7'48″ = 0.64435011088 rad
∠ C' = γ' = 90° = 1.57107963268 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     