Triangle calculator SAS

Please enter two sides of the triangle and the included angle
°


Right isosceles triangle.

Sides: a = 600   b = 600   c = 848.5288137424

Area: T = 180000
Perimeter: p = 2048.528813742
Semiperimeter: s = 1024.264406871

Angle ∠ A = α = 45° = 0.78553981634 rad
Angle ∠ B = β = 45° = 0.78553981634 rad
Angle ∠ C = γ = 90° = 1.57107963268 rad

Height: ha = 600
Height: hb = 600
Height: hc = 424.2644068712

Median: ma = 670.822039325
Median: mb = 670.822039325
Median: mc = 424.2644068712

Inradius: r = 175.7365931288
Circumradius: R = 424.2644068712

Vertex coordinates: A[848.5288137424; 0] B[0; 0] C[424.2644068712; 424.2644068712]
Centroid: CG[424.2644068712; 141.4211356237]
Coordinates of the circumscribed circle: U[424.2644068712; 0]
Coordinates of the inscribed circle: I[424.2644068712; 175.7365931288]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 135° = 0.78553981634 rad
∠ B' = β' = 135° = 0.78553981634 rad
∠ C' = γ' = 90° = 1.57107963268 rad

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How did we calculate this triangle?

1. Calculation of the third side c of the triangle using a Law of Cosines

a = 600 ; ; b = 600 ; ; gamma = 90° ; ; ; ; c**2 = a**2+b**2 - 2ab cos( gamma ) ; ; c = sqrt{ a**2+b**2 - 2ab cos( gamma ) } ; ; c = sqrt{ 600**2+600**2 - 2 * 600 * 600 * cos(90° ) } ; ; c = 848.53 ; ;


Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a = 600 ; ; b = 600 ; ; c = 848.53 ; ;

2. The triangle circumference is the sum of the lengths of its three sides

p = a+b+c = 600+600+848.53 = 2048.53 ; ;

3. Semiperimeter of the triangle

s = fraction{ o }{ 2 } = fraction{ 2048.53 }{ 2 } = 1024.26 ; ;

4. The triangle area using Heron's formula

T = sqrt{ s(s-a)(s-b)(s-c) } ; ; T = sqrt{ 1024.26 * (1024.26-600)(1024.26-600)(1024.26-848.53) } ; ; T = sqrt{ 32400000000 } = 180000 ; ;

5. Calculate the heights of the triangle from its area.

T = fraction{ a h _a }{ 2 } ; ; h _a = fraction{ 2 T }{ a } = fraction{ 2 * 180000 }{ 600 } = 600 ; ; h _b = fraction{ 2 T }{ b } = fraction{ 2 * 180000 }{ 600 } = 600 ; ; h _c = fraction{ 2 T }{ c } = fraction{ 2 * 180000 }{ 848.53 } = 424.26 ; ;

6. Calculation of the inner angles of the triangle using a Law of Cosines

a**2 = b**2+c**2 - 2bc cos( alpha ) ; ; alpha = arccos( fraction{ a**2-b**2-c**2 }{ 2bc } ) = arccos( fraction{ 600**2-600**2-848.53**2 }{ 2 * 600 * 848.53 } ) = 45° ; ; beta = arccos( fraction{ b**2-a**2-c**2 }{ 2ac } ) = arccos( fraction{ 600**2-600**2-848.53**2 }{ 2 * 600 * 848.53 } ) = 45° ; ; gamma = arccos( fraction{ c**2-a**2-b**2 }{ 2ba } ) = arccos( fraction{ 848.53**2-600**2-600**2 }{ 2 * 600 * 600 } ) = 90° ; ;

7. Inradius

T = rs ; ; r = fraction{ T }{ s } = fraction{ 180000 }{ 1024.26 } = 175.74 ; ;

8. Circumradius

R = fraction{ a }{ 2 * sin( alpha ) } = fraction{ 600 }{ 2 * sin 45° } = 424.26 ; ;




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