# 6.5 14.1 10.2 triangle

### Obtuse scalene triangle.

Sides: a = 6.5   b = 14.1   c = 10.2

Area: T = 30.43988830281
Perimeter: p = 30.8
Semiperimeter: s = 15.4

Angle ∠ A = α = 25.04325610751° = 25°2'33″ = 0.43770751439 rad
Angle ∠ B = β = 113.3333250051° = 113°20' = 1.97880383654 rad
Angle ∠ C = γ = 41.62441888734° = 41°37'27″ = 0.72664791443 rad

Height: ha = 9.36658101625
Height: hb = 4.31875720607
Height: hc = 5.96884084369

Median: ma = 11.86985508804
Median: mb = 4.8421745553
Median: mc = 9.72221396822

Inradius: r = 1.9776550846
Circumradius: R = 7.67879262821

Vertex coordinates: A[10.2; 0] B[0; 0] C[-2.57545098039; 5.96884084369]
Centroid: CG[2.54218300654; 1.9899469479]
Coordinates of the circumscribed circle: U[5.1; 5.73993860293]
Coordinates of the inscribed circle: I[1.3; 1.9776550846]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 154.9577438925° = 154°57'27″ = 0.43770751439 rad
∠ B' = β' = 66.66767499485° = 66°40' = 1.97880383654 rad
∠ C' = γ' = 138.3765811127° = 138°22'33″ = 0.72664791443 rad

# How did we calculate this triangle?

### 1. The triangle circumference is the sum of the lengths of its three sides ### 2. Semiperimeter of the triangle ### 3. The triangle area using Heron's formula ### 4. Calculate the heights of the triangle from its area. ### 5. Calculation of the inner angles of the triangle using a Law of Cosines    