52.15 48 60 triangle

Acute scalene triangle.

Sides: a = 52.15   b = 48   c = 60

Area: T = 1199.931072554
Perimeter: p = 160.15
Semiperimeter: s = 80.075

Angle ∠ A = α = 56.43877041527° = 56°26'16″ = 0.98550237597 rad
Angle ∠ B = β = 50.08329233523° = 50°4'59″ = 0.87441119115 rad
Angle ∠ C = γ = 73.47993724951° = 73°28'46″ = 1.28224569823 rad

Height: ha = 46.01884362623
Height: hb = 49.99771135641
Height: hc = 39.99876908513

Median: ma = 47.66664911127
Median: mb = 50.83112035073
Median: mc = 40.14773691542

Inradius: r = 14.98550855515
Circumradius: R = 31.29218064358

Vertex coordinates: A[60; 0] B[0; 0] C[33.46435208333; 39.99876908513]
Centroid: CG[31.15545069444; 13.33325636171]
Coordinates of the circumscribed circle: U[30; 8.8988154304]
Coordinates of the inscribed circle: I[32.075; 14.98550855515]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 123.5622295847° = 123°33'44″ = 0.98550237597 rad
∠ B' = β' = 129.9177076648° = 129°55'1″ = 0.87441119115 rad
∠ C' = γ' = 106.5210627505° = 106°31'14″ = 1.28224569823 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     