# 400 900 984.9 triangle

### Obtuse scalene triangle.

Sides: a = 400   b = 900   c = 984.9

Area: T = 1800009.999864
Perimeter: p = 2284.9
Semiperimeter: s = 1142.45

Angle ∠ A = α = 23.96221212995° = 23°57'44″ = 0.41882179124 rad
Angle ∠ B = β = 66.03656497356° = 66°2'8″ = 1.15325395116 rad
Angle ∠ C = γ = 90.0022228965° = 90°8″ = 1.57108352296 rad

Height: ha = 9009.999999319
Height: hb = 4009.999999697
Height: hc = 365.5199341789

Median: ma = 921.9622040976
Median: mb = 602.0911359347
Median: mc = 492.4365780077

Inradius: r = 157.5566129252
Circumradius: R = 492.4550000373

Vertex coordinates: A[984.9; 0] B[0; 0] C[162.4677260636; 365.5199341789]
Centroid: CG[382.4565753545; 121.8439780596]
Coordinates of the circumscribed circle: U[492.45; -0.01991576729]
Coordinates of the inscribed circle: I[242.45; 157.5566129252]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 156.0387878701° = 156°2'16″ = 0.41882179124 rad
∠ B' = β' = 113.9644350264° = 113°57'52″ = 1.15325395116 rad
∠ C' = γ' = 89.9987771035° = 89°59'52″ = 1.57108352296 rad

# How did we calculate this triangle?

### 1. The triangle circumference is the sum of the lengths of its three sides ### 2. Semiperimeter of the triangle ### 3. The triangle area using Heron's formula ### 4. Calculate the heights of the triangle from its area. ### 5. Calculation of the inner angles of the triangle using a Law of Cosines    