400 599 320 triangle

Obtuse scalene triangle.

Sides: a = 400   b = 599   c = 320

Area: T = 59288.93661512
Perimeter: p = 1319
Semiperimeter: s = 659.5

Angle ∠ A = α = 38.21657302689° = 38°12'57″ = 0.66769903192 rad
Angle ∠ B = β = 112.121115944° = 112°7'16″ = 1.95768833934 rad
Angle ∠ C = γ = 29.66331102915° = 29°39'47″ = 0.5187718941 rad

Height: ha = 296.4454680756
Height: hb = 197.9659720037
Height: hc = 370.5565850945

Median: ma = 436.5788171694
Median: mb = 203.7154874273
Median: mc = 483.5299213182

Inradius: r = 89.9899827371
Circumradius: R = 323.2988093107

Vertex coordinates: A[320; 0] B[0; 0] C[-150.62765625; 370.5565850945]
Centroid: CG[56.45878125; 123.5198616982]
Coordinates of the circumscribed circle: U[160; 280.9329985951]
Coordinates of the inscribed circle: I[60.5; 89.9899827371]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 141.7844269731° = 141°47'3″ = 0.66769903192 rad
∠ B' = β' = 67.87988405604° = 67°52'44″ = 1.95768833934 rad
∠ C' = γ' = 150.3376889708° = 150°20'13″ = 0.5187718941 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     