40 40 40 triangle

Equilateral triangle.

Sides: a = 40   b = 40   c = 40

Area: T = 692.8220323028
Perimeter: p = 120
Semiperimeter: s = 60

Angle ∠ A = α = 60° = 1.04771975512 rad
Angle ∠ B = β = 60° = 1.04771975512 rad
Angle ∠ C = γ = 60° = 1.04771975512 rad

Height: ha = 34.64110161514
Height: hb = 34.64110161514
Height: hc = 34.64110161514

Median: ma = 34.64110161514
Median: mb = 34.64110161514
Median: mc = 34.64110161514

Inradius: r = 11.54770053838
Circumradius: R = 23.09440107676

Vertex coordinates: A[40; 0] B[0; 0] C[20; 34.64110161514]
Centroid: CG[20; 11.54770053838]
Coordinates of the circumscribed circle: U[20; 11.54770053838]
Coordinates of the inscribed circle: I[20; 11.54770053838]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 120° = 1.04771975512 rad
∠ B' = β' = 120° = 1.04771975512 rad
∠ C' = γ' = 120° = 1.04771975512 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    