300 77.65 289.78 triangle

Acute scalene triangle.

Sides: a = 300   b = 77.65   c = 289.78

Area: T = 11250.70884892
Perimeter: p = 667.43
Semiperimeter: s = 333.715

Angle ∠ A = α = 89.99774907302° = 89°59'51″ = 1.57107525318 rad
Angle ∠ B = β = 15.00108475213° = 15°3″ = 0.26218141798 rad
Angle ∠ C = γ = 75.00216617485° = 75°6″ = 1.3099025942 rad

Height: ha = 75.00547232614
Height: hb = 289.7879999722
Height: hc = 77.65499999255

Median: ma = 150.0033284797
Median: mb = 292.3687651383
Median: mc = 164.3832630317

Inradius: r = 33.71435234832
Circumradius: R = 1500.000000144

Vertex coordinates: A[289.78; 0] B[0; 0] C[289.7776599317; 77.65499999255]
Centroid: CG[193.1865533106; 25.88333333085]
Coordinates of the circumscribed circle: U[144.89; 38.81986545768]
Coordinates of the inscribed circle: I[256.065; 33.71435234832]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 90.00325092698° = 90°9″ = 1.57107525318 rad
∠ B' = β' = 164.9999152479° = 164°59'57″ = 0.26218141798 rad
∠ C' = γ' = 104.9988338252° = 104°59'54″ = 1.3099025942 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     