# 300 300 424.26 triangle

### Acute isosceles triangle.

Sides: a = 300   b = 300   c = 424.26

Area: T = 450009.9999917
Perimeter: p = 1024.26
Semiperimeter: s = 512.13

Angle ∠ A = α = 45.00105494665° = 45°2″ = 0.78554077534 rad
Angle ∠ B = β = 45.00105494665° = 45°2″ = 0.78554077534 rad
Angle ∠ C = γ = 89.99989010669° = 89°59'56″ = 1.57107771468 rad

Height: ha = 3009.999999945
Height: hb = 3009.999999945
Height: hc = 212.1344068692

Median: ma = 335.4087623348
Median: mb = 335.4087623348
Median: mc = 212.1344068692

Inradius: r = 87.86883146696
Circumradius: R = 212.1330000039

Vertex coordinates: A[424.26; 0] B[0; 0] C[212.13; 212.1344068692]
Centroid: CG[212.13; 70.71113562308]
Coordinates of the circumscribed circle: U[212.13; 0.00440686534]
Coordinates of the inscribed circle: I[212.13; 87.86883146696]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 134.9999450533° = 134°59'58″ = 0.78554077534 rad
∠ B' = β' = 134.9999450533° = 134°59'58″ = 0.78554077534 rad
∠ C' = γ' = 90.00110989331° = 90°4″ = 1.57107771468 rad

# How did we calculate this triangle?

### 1. The triangle circumference is the sum of the lengths of its three sides ### 2. Semiperimeter of the triangle ### 3. The triangle area using Heron's formula ### 4. Calculate the heights of the triangle from its area. ### 5. Calculation of the inner angles of the triangle using a Law of Cosines    