3.5 3.9 2.2 triangle

Acute scalene triangle.

Sides: a = 3.5   b = 3.9   c = 2.2

Area: T = 3.82112039987
Perimeter: p = 9.6
Semiperimeter: s = 4.8

Angle ∠ A = α = 62.96443082106° = 62°57'52″ = 1.09989344895 rad
Angle ∠ B = β = 82.98879594194° = 82°59'17″ = 1.44884131314 rad
Angle ∠ C = γ = 34.048773237° = 34°2'52″ = 0.59442450327 rad

Height: ha = 2.18435451421
Height: hb = 1.96595917942
Height: hc = 3.4743821817

Median: ma = 2.63986549604
Median: mb = 2.1787728174
Median: mc = 3.53883612026

Inradius: r = 0.79660841664
Circumradius: R = 1.96546948979

Vertex coordinates: A[2.2; 0] B[0; 0] C[0.42772727273; 3.4743821817]
Centroid: CG[0.87657575758; 1.15879406057]
Coordinates of the circumscribed circle: U[1.1; 1.62878900582]
Coordinates of the inscribed circle: I[0.9; 0.79660841664]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 117.0365691789° = 117°2'8″ = 1.09989344895 rad
∠ B' = β' = 97.01220405806° = 97°43″ = 1.44884131314 rad
∠ C' = γ' = 145.952226763° = 145°57'8″ = 0.59442450327 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     