22615 26544 19782 triangle

Acute scalene triangle.

Sides: a = 22615   b = 26544   c = 19782

Area: T = 218128887.654
Perimeter: p = 68941
Semiperimeter: s = 34470.5

Angle ∠ A = α = 56.18329995073° = 56°10'59″ = 0.9810578325 rad
Angle ∠ B = β = 77.20330508408° = 77°12'11″ = 1.34774474298 rad
Angle ∠ C = γ = 46.61439496519° = 46°36'50″ = 0.81435668988 rad

Height: ha = 19290.63878646
Height: hb = 16435.26988106
Height: hc = 22053.26994019

Median: ma = 20496.24877969
Median: mb = 16590.26549316
Median: mc = 22587.14767764

Inradius: r = 6327.987734147
Circumradius: R = 13610.05881973

Vertex coordinates: A[19782; 0] B[0; 0] C[5009.145500556; 22053.26994019]
Centroid: CG[8263.715500185; 7351.098980064]
Coordinates of the circumscribed circle: U[9891; 9348.893315015]
Coordinates of the inscribed circle: I[7926.5; 6327.987734147]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 123.8177000493° = 123°49'1″ = 0.9810578325 rad
∠ B' = β' = 102.7976949159° = 102°47'49″ = 1.34774474298 rad
∠ C' = γ' = 133.3866050348° = 133°23'10″ = 0.81435668988 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     