# Triangle calculator SSA

Please enter two sides and a non-included angle
°

Triangle has two solutions with side c=322.8711376228 and with side c=23.53987852859

### #1 Obtuse scalene triangle.

Sides: a = 200   b = 180   c = 322.8711376228

Area: T = 16143.56988114
Perimeter: p = 702.8711376228
Semiperimeter: s = 351.4365688114

Angle ∠ A = α = 33.74989885959° = 33°44'56″ = 0.58990309702 rad
Angle ∠ B = β = 30° = 0.52435987756 rad
Angle ∠ C = γ = 116.2511011404° = 116°15'4″ = 2.02989629078 rad

Height: ha = 161.4365688114
Height: hb = 179.3732986793
Height: hc = 100

Median: ma = 241.5011475759
Median: mb = 253.0287592949
Median: mc = 100.6990211059

Inradius: r = 45.9366054184
Circumradius: R = 180

Vertex coordinates: A[322.8711376228; 0] B[0; 0] C[173.2055080757; 100]
Centroid: CG[165.3598818995; 33.33333333333]
Coordinates of the circumscribed circle: U[161.4365688114; -79.61548139682]
Coordinates of the inscribed circle: I[171.4365688114; 45.9366054184]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 146.2511011404° = 146°15'4″ = 0.58990309702 rad
∠ B' = β' = 150° = 0.52435987756 rad
∠ C' = γ' = 63.74989885959° = 63°44'56″ = 2.02989629078 rad

# How did we calculate this triangle?

### 1. Use Law of Cosines  Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. ### 2. The triangle circumference is the sum of the lengths of its three sides ### 3. Semiperimeter of the triangle ### 4. The triangle area using Heron's formula ### 5. Calculate the heights of the triangle from its area. ### 6. Calculation of the inner angles of the triangle using a Law of Cosines ### 7. Inradius ### 8. Circumradius ### 9. Calculation of medians ### #2 Obtuse scalene triangle.

Sides: a = 200   b = 180   c = 23.53987852859

Area: T = 1176.93992643
Perimeter: p = 403.5398785286
Semiperimeter: s = 201.7699392643

Angle ∠ A = α = 146.2511011404° = 146°15'4″ = 2.55325616834 rad
Angle ∠ B = β = 30° = 0.52435987756 rad
Angle ∠ C = γ = 3.74989885959° = 3°44'56″ = 0.06554321946 rad

Height: ha = 11.7699392643
Height: hb = 13.07771029366
Height: hc = 100

Median: ma = 80.48800422861
Median: mb = 110.3549613531
Median: mc = 189.8998608201

Inradius: r = 5.83330911784
Circumradius: R = 180

Vertex coordinates: A[23.53987852859; 0] B[0; 0] C[173.2055080757; 100]
Centroid: CG[65.58112886809; 33.33333333333]
Coordinates of the circumscribed circle: U[11.7699392643; 179.6154813968]
Coordinates of the inscribed circle: I[21.7699392643; 5.83330911784]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 33.74989885959° = 33°44'56″ = 2.55325616834 rad
∠ B' = β' = 150° = 0.52435987756 rad
∠ C' = γ' = 176.2511011404° = 176°15'4″ = 0.06554321946 rad

# How did we calculate this triangle?

### 1. Use Law of Cosines  Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. ### 2. The triangle circumference is the sum of the lengths of its three sides ### 3. Semiperimeter of the triangle ### 4. The triangle area using Heron's formula ### 5. Calculate the heights of the triangle from its area. ### 6. Calculation of the inner angles of the triangle using a Law of Cosines ### 7. Inradius ### 8. Circumradius ### 9. Calculation of medians #### Look also our friend's collection of math examples and problems:

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