# 2.7 3.9 4.3 triangle

### Acute scalene triangle.

Sides: a = 2.7   b = 3.9   c = 4.3

Area: T = 5.16986766923
Perimeter: p = 10.9
Semiperimeter: s = 5.45

Angle ∠ A = α = 38.05551291715° = 38°3'18″ = 0.66441873013 rad
Angle ∠ B = β = 62.9211487232° = 62°55'17″ = 1.09881871225 rad
Angle ∠ C = γ = 79.02333835965° = 79°1'24″ = 1.37992182298 rad

Height: ha = 3.82986494017
Height: hb = 2.6510603432
Height: hc = 2.40440356709

Median: ma = 3.87765319552
Median: mb = 3.0154548059
Median: mc = 2.57443931324

Inradius: r = 0.94883810445
Circumradius: R = 2.19900673371

Vertex coordinates: A[4.3; 0] B[0; 0] C[1.22990697674; 2.40440356709]
Centroid: CG[1.84330232558; 0.80113452236]
Coordinates of the circumscribed circle: U[2.15; 0.41770071235]
Coordinates of the inscribed circle: I[1.55; 0.94883810445]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 141.9454870828° = 141°56'42″ = 0.66441873013 rad
∠ B' = β' = 117.0798512768° = 117°4'43″ = 1.09881871225 rad
∠ C' = γ' = 100.9776616404° = 100°58'36″ = 1.37992182298 rad

# How did we calculate this triangle?

### 1. The triangle circumference is the sum of the lengths of its three sides ### 2. Semiperimeter of the triangle ### 3. The triangle area using Heron's formula ### 4. Calculate the heights of the triangle from its area. ### 5. Calculation of the inner angles of the triangle using a Law of Cosines    