146.2 209.3 191.41 triangle

Acute scalene triangle.

Sides: a = 146.2   b = 209.3   c = 191.41

Area: T = 13533.8659896
Perimeter: p = 546.91
Semiperimeter: s = 273.455

Angle ∠ A = α = 42.50441679106° = 42°30'15″ = 0.74218376759 rad
Angle ∠ B = β = 75.29664635734° = 75°17'47″ = 1.31441712045 rad
Angle ∠ C = γ = 62.1999368516° = 62°11'58″ = 1.08655837733 rad

Height: ha = 185.1421722243
Height: hb = 129.3254987061
Height: hc = 141.4122255326

Median: ma = 186.7587942401
Median: mb = 134.3677003204
Median: mc = 153.0721937255

Inradius: r = 49.49220915543
Circumradius: R = 108.1933098008

Vertex coordinates: A[191.41; 0] B[0; 0] C[37.10881398569; 141.4122255326]
Centroid: CG[76.17327132856; 47.1377418442]
Coordinates of the circumscribed circle: U[95.705; 50.46108703012]
Coordinates of the inscribed circle: I[64.155; 49.49220915543]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 137.4965832089° = 137°29'45″ = 0.74218376759 rad
∠ B' = β' = 104.7043536427° = 104°42'13″ = 1.31441712045 rad
∠ C' = γ' = 117.8010631484° = 117°48'2″ = 1.08655837733 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     