# 142 142 190 triangle

### Acute isosceles triangle.

Sides: a = 142   b = 142   c = 190

Area: T = 10026.43987995
Perimeter: p = 474
Semiperimeter: s = 237

Angle ∠ A = α = 48.00989830931° = 48°32″ = 0.83879148255 rad
Angle ∠ B = β = 48.00989830931° = 48°32″ = 0.83879148255 rad
Angle ∠ C = γ = 83.98220338138° = 83°58'55″ = 1.46657630026 rad

Height: ha = 141.217744788
Height: hb = 141.217744788
Height: hc = 105.5411461047

Median: ma = 151.9577230825
Median: mb = 151.9577230825
Median: mc = 105.5411461047

Inradius: r = 42.3065648943
Circumradius: R = 95.52664395618

Vertex coordinates: A[190; 0] B[0; 0] C[95; 105.5411461047]
Centroid: CG[95; 35.18804870158]
Coordinates of the circumscribed circle: U[95; 10.01550214855]
Coordinates of the inscribed circle: I[95; 42.3065648943]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 131.9911016907° = 131°59'28″ = 0.83879148255 rad
∠ B' = β' = 131.9911016907° = 131°59'28″ = 0.83879148255 rad
∠ C' = γ' = 96.01879661862° = 96°1'5″ = 1.46657630026 rad

# How did we calculate this triangle?

### 1. The triangle circumference is the sum of the lengths of its three sides ### 2. Semiperimeter of the triangle ### 3. The triangle area using Heron's formula ### 4. Calculate the heights of the triangle from its area. ### 5. Calculation of the inner angles of the triangle using a Law of Cosines    