141 145 49.82 triangle

Acute scalene triangle.

Sides: a = 141   b = 145   c = 49.82

Area: T = 3496.345464364
Perimeter: p = 335.82
Semiperimeter: s = 167.91

Angle ∠ A = α = 75.46548020732° = 75°27'53″ = 1.31771092655 rad
Angle ∠ B = β = 84.53549371046° = 84°32'6″ = 1.47554129854 rad
Angle ∠ C = γ = 200.0002608222° = 20°1″ = 0.34990704026 rad

Height: ha = 49.59435410446
Height: hb = 48.22554433606
Height: hc = 140.3599078428

Median: ma = 82.36105864476
Median: mb = 76.97657507271
Median: mc = 140.8287880407

Inradius: r = 20.82327302939
Circumradius: R = 72.83110567046

Vertex coordinates: A[49.82; 0] B[0; 0] C[13.42986672019; 140.3599078428]
Centroid: CG[21.08328890673; 46.7866359476]
Coordinates of the circumscribed circle: U[24.91; 68.43986931546]
Coordinates of the inscribed circle: I[22.91; 20.82327302939]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 104.5355197927° = 104°32'7″ = 1.31771092655 rad
∠ B' = β' = 95.46550628954° = 95°27'54″ = 1.47554129854 rad
∠ C' = γ' = 1609.999739178° = 159°59'59″ = 0.34990704026 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     