# 136 206 110 triangle

### Obtuse scalene triangle.

Sides: a = 136   b = 206   c = 110

Area: T = 6869.411045505
Perimeter: p = 452
Semiperimeter: s = 226

Angle ∠ A = α = 37.32326470536° = 37°19'22″ = 0.65114030766 rad
Angle ∠ B = β = 113.311100629° = 113°18'40″ = 1.97876501385 rad
Angle ∠ C = γ = 29.36663466567° = 29°21'59″ = 0.51325394384 rad

Height: ha = 101.0210741986
Height: hb = 66.69333053889
Height: hc = 124.898837191

Median: ma = 150.4799234448
Median: mb = 68.47662732631
Median: mc = 165.6533252307

Inradius: r = 30.39656214825
Circumradius: R = 112.1555184938

Vertex coordinates: A[110; 0] B[0; 0] C[-53.81881818182; 124.898837191]
Centroid: CG[18.72772727273; 41.63327906367]
Coordinates of the circumscribed circle: U[55; 97.74334678555]
Coordinates of the inscribed circle: I[20; 30.39656214825]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 142.6777352946° = 142°40'38″ = 0.65114030766 rad
∠ B' = β' = 66.68989937103° = 66°41'20″ = 1.97876501385 rad
∠ C' = γ' = 150.6343653343° = 150°38'1″ = 0.51325394384 rad

# How did we calculate this triangle?

### 1. The triangle circumference is the sum of the lengths of its three sides ### 2. Semiperimeter of the triangle ### 3. The triangle area using Heron's formula ### 4. Calculate the heights of the triangle from its area. ### 5. Calculation of the inner angles of the triangle using a Law of Cosines    