101.36 158.67 220.25 triangle

Obtuse scalene triangle.

Sides: a = 101.36   b = 158.67   c = 220.25

Area: T = 7348.724413182
Perimeter: p = 480.28
Semiperimeter: s = 240.14

Angle ∠ A = α = 24.87701456524° = 24°52'13″ = 0.43440659271 rad
Angle ∠ B = β = 41.17444533421° = 41°10'28″ = 0.71986297785 rad
Angle ∠ C = γ = 113.9555401005° = 113°57'19″ = 1.9898896948 rad

Height: ha = 145.0022449326
Height: hb = 92.62990304635
Height: hc = 66.73107526158

Median: ma = 185.134414947
Median: mb = 151.9879978369
Median: mc = 74.81663994389

Inradius: r = 30.60218328134
Circumradius: R = 120.505509375

Vertex coordinates: A[220.25; 0] B[0; 0] C[76.29545362089; 66.73107526158]
Centroid: CG[98.84881787363; 22.24435842053]
Coordinates of the circumscribed circle: U[110.125; -48.92881309143]
Coordinates of the inscribed circle: I[81.47; 30.60218328134]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 155.1329854348° = 155°7'47″ = 0.43440659271 rad
∠ B' = β' = 138.8265546658° = 138°49'32″ = 0.71986297785 rad
∠ C' = γ' = 66.04545989946° = 66°2'41″ = 1.9898896948 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     