100 141 100 triangle

Acute isosceles triangle.

Sides: a = 100   b = 141   c = 100

Area: T = 4999.911149297
Perimeter: p = 341
Semiperimeter: s = 170.5

Angle ∠ A = α = 45.17704559498° = 45°10'14″ = 0.7888373181 rad
Angle ∠ B = β = 89.65990881004° = 89°39'33″ = 1.56548462917 rad
Angle ∠ C = γ = 45.17704559498° = 45°10'14″ = 0.7888373181 rad

Height: ha = 99.99882298593
Height: hb = 70.92107303967
Height: hc = 99.99882298593

Median: ma = 111.537698938
Median: mb = 70.92107303967
Median: mc = 111.537698938

Inradius: r = 29.32549940936
Circumradius: R = 70.50112479713

Vertex coordinates: A[100; 0] B[0; 0] C[0.595; 99.99882298593]
Centroid: CG[33.53216666667; 33.33327432864]
Coordinates of the circumscribed circle: U[50; 49.70333798197]
Coordinates of the inscribed circle: I[29.5; 29.32549940936]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 134.832954405° = 134°49'46″ = 0.7888373181 rad
∠ B' = β' = 90.34109118996° = 90°20'27″ = 1.56548462917 rad
∠ C' = γ' = 134.832954405° = 134°49'46″ = 0.7888373181 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     