# 100 120 150 triangle

### Acute scalene triangle.

Sides: a = 100   b = 120   c = 150

Area: T = 5981.168836412
Perimeter: p = 370
Semiperimeter: s = 185

Angle ∠ A = α = 41.65496722739° = 41°38'59″ = 0.72769239136 rad
Angle ∠ B = β = 52.89109950542° = 52°53'28″ = 0.92331220084 rad
Angle ∠ C = γ = 85.45993326719° = 85°27'34″ = 1.49215467317 rad

Height: ha = 119.6233367282
Height: hb = 99.68661394021
Height: hc = 79.74989115217

Median: ma = 126.2933309403
Median: mb = 112.4722218792
Median: mc = 81.08663737011

Inradius: r = 32.33106398061
Circumradius: R = 75.23661365882

Vertex coordinates: A[150; 0] B[0; 0] C[60.33333333333; 79.74989115217]
Centroid: CG[70.11111111111; 26.58329705072]
Coordinates of the circumscribed circle: U[75; 5.95661941466]
Coordinates of the inscribed circle: I[65; 32.33106398061]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 138.3550327726° = 138°21'1″ = 0.72769239136 rad
∠ B' = β' = 127.1099004946° = 127°6'32″ = 0.92331220084 rad
∠ C' = γ' = 94.54106673281° = 94°32'26″ = 1.49215467317 rad

# How did we calculate this triangle?

### 1. The triangle circumference is the sum of the lengths of its three sides ### 2. Semiperimeter of the triangle ### 3. The triangle area using Heron's formula ### 4. Calculate the heights of the triangle from its area. ### 5. Calculation of the inner angles of the triangle using a Law of Cosines ### 6. Inradius ### 7. Circumradius ### 8. Calculation of medians #### Look also our friend's collection of math examples and problems:

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