Triangle calculator SSA

Please enter two sides and a non-included angle
°


Triangle has two solutions with side c=170.0911070979 and with side c=11.17704864286

#1 Obtuse scalene triangle.

Sides: a = 100   b = 90   c = 170.0911070979

Area: T = 3594.187963773
Perimeter: p = 360.0911070979
Semiperimeter: s = 180.0465535489

Angle ∠ A = α = 28.00767673296° = 28°24″ = 0.48988103027 rad
Angle ∠ B = β = 25° = 0.4366332313 rad
Angle ∠ C = γ = 126.993323267° = 126°59'36″ = 2.21664500378 rad

Height: ha = 71.88435927546
Height: hb = 79.87106586163
Height: hc = 42.26218261741

Median: ma = 126.5522306235
Median: mb = 132.0622433013
Median: mc = 42.62992961862

Inradius: r = 19.96326146128
Circumradius: R = 106.4799071242

Vertex coordinates: A[170.0911070979; 0] B[0; 0] C[90.63107787037; 42.26218261741]
Centroid: CG[86.90772832275; 14.08772753914]
Coordinates of the circumscribed circle: U[85.04655354893; -64.07106602577]
Coordinates of the inscribed circle: I[90.04655354893; 19.96326146128]

Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 151.993323267° = 151°59'36″ = 0.48988103027 rad
∠ B' = β' = 155° = 0.4366332313 rad
∠ C' = γ' = 53.00767673296° = 53°24″ = 2.21664500378 rad


How did we calculate this triangle?

The calculation of the triangle progress in two phases. The first phase is such that we try to calculate all three sides of the triangle from the input parameters. The first phase is different for the different triangles query entered. The second phase is the calculation of other characteristics of the triangle, such as angles, area, perimeter, heights, the center of gravity, circle radii, etc. Some input data also results in two to three correct triangle solutions (e.g., if the specified triangle area and two sides - typically resulting in both acute and obtuse) triangle).

1. Use the Law of Cosines

a=100 b=90 β=25  b2=a2+c22accosβ 902=1002+c22 100 c cos(25)  c2181.262c+1900=0  p=1;q=181.262;r=1900 D=q24pr=181.2622411900=25255.7521937 D>0  c1,2=q±D2p=181.26±25255.752 c1,2=90.6307787±79.460292275 c1=170.091070979 c2=11.1704864286   Factored form of the equation:  (c170.091070979)(c11.1704864286)=0   c>0a = 100 \ \\ b = 90 \ \\ β = 25^\circ \ \\ \ \\ b^2 = a^2 + c^2 - 2ac \cos β \ \\ 90^2 = 100^2 + c^2 -2 \cdot \ 100 \cdot \ c \cdot \ \cos (25^\circ ) \ \\ \ \\ c^2 -181.262c +1900 =0 \ \\ \ \\ p=1; q=-181.262; r=1900 \ \\ D = q^2 - 4pr = 181.262^2 - 4\cdot 1 \cdot 1900 = 25255.7521937 \ \\ D>0 \ \\ \ \\ c_{1,2} = \dfrac{ -q \pm \sqrt{ D } }{ 2p } = \dfrac{ 181.26 \pm \sqrt{ 25255.75 } }{ 2 } \ \\ c_{1,2} = 90.6307787 \pm 79.460292275 \ \\ c_{1} = 170.091070979 \ \\ c_{2} = 11.1704864286 \ \\ \ \\ \text{ Factored form of the equation: } \ \\ (c -170.091070979) (c -11.1704864286) = 0 \ \\ \ \\ \ \\ c>0

Now we know the lengths of all three sides of the triangle, and the triangle is uniquely determined. Next, we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a=100 b=90 c=170.09a = 100 \ \\ b = 90 \ \\ c = 170.09

2. The triangle perimeter is the sum of the lengths of its three sides

p=a+b+c=100+90+170.09=360.09p = a+b+c = 100+90+170.09 = 360.09

3. Semiperimeter of the triangle

The semiperimeter of the triangle is half its perimeter. The semiperimeter frequently appears in formulas for triangles that it is given a separate name. By the triangle inequality, the longest side length of a triangle is less than the semiperimeter.

s=p2=360.092=180.05s = \dfrac{ p }{ 2 } = \dfrac{ 360.09 }{ 2 } = 180.05

4. The triangle area using Heron's formula

Heron's formula gives the area of a triangle when the length of all three sides are known. There is no need to calculate angles or other distances in the triangle first. Heron's formula works equally well in all cases and types of triangles.

T=s(sa)(sb)(sc) T=180.05(180.05100)(180.0590)(180.05170.09) T=12918127.27=3594.18T = \sqrt{ s(s-a)(s-b)(s-c) } \ \\ T = \sqrt{ 180.05(180.05-100)(180.05-90)(180.05-170.09) } \ \\ T = \sqrt{ 12918127.27 } = 3594.18

5. Calculate the heights of the triangle from its area.

There are many ways to find the height of the triangle. The easiest way is from the area and base length. The area of a triangle is half of the product of the length of the base and the height. Every side of the triangle can be a base; there are three bases and three heights (altitudes). Triangle height is the perpendicular line segment from a vertex to a line containing the base.

T=aha2  ha=2 Ta=2 3594.18100=71.88 hb=2 Tb=2 3594.1890=79.87 hc=2 Tc=2 3594.18170.09=42.26T = \dfrac{ a h _a }{ 2 } \ \\ \ \\ h _a = \dfrac{ 2 \ T }{ a } = \dfrac{ 2 \cdot \ 3594.18 }{ 100 } = 71.88 \ \\ h _b = \dfrac{ 2 \ T }{ b } = \dfrac{ 2 \cdot \ 3594.18 }{ 90 } = 79.87 \ \\ h _c = \dfrac{ 2 \ T }{ c } = \dfrac{ 2 \cdot \ 3594.18 }{ 170.09 } = 42.26

6. Calculation of the inner angles of the triangle using a Law of Cosines

The Law of Cosines is useful for finding the angles of a triangle when we know all three sides. The cosine rule, also known as the law of cosines, relates all three sides of a triangle with an angle of a triangle. The Law of Cosines is the extrapolation of the Pythagorean theorem for any triangle. Pythagorean theorem works only in a right triangle. Pythagorean theorem is a special case of the Law of Cosines and can be derived from it because the cosine of 90° is 0. It is best to find the angle opposite the longest side first. With the Law of Cosines, there is also no problem with obtuse angles as with the Law of Sines, because cosine function is negative for obtuse angles, zero for right, and positive for acute angles. We also use inverse cosine called arccosine to determine the angle from cosine value.

a2=b2+c22bccosα  α=arccos(b2+c2a22bc)=arccos(902+170.09210022 90 170.09)=2824"  b2=a2+c22accosβ β=arccos(a2+c2b22ac)=arccos(1002+170.0929022 100 170.09)=25 γ=180αβ=1802824"25=1265936"a^2 = b^2+c^2 - 2bc \cos α \ \\ \ \\ α = \arccos(\dfrac{ b^2+c^2-a^2 }{ 2bc } ) = \arccos(\dfrac{ 90^2+170.09^2-100^2 }{ 2 \cdot \ 90 \cdot \ 170.09 } ) = 28^\circ 24" \ \\ \ \\ b^2 = a^2+c^2 - 2ac \cos β \ \\ β = \arccos(\dfrac{ a^2+c^2-b^2 }{ 2ac } ) = \arccos(\dfrac{ 100^2+170.09^2-90^2 }{ 2 \cdot \ 100 \cdot \ 170.09 } ) = 25^\circ \ \\ γ = 180^\circ - α - β = 180^\circ - 28^\circ 24" - 25^\circ = 126^\circ 59'36"

7. Inradius

An incircle of a triangle is a circle which is tangent to each side. An incircle center is called incenter and has a radius named inradius. All triangles have an incenter, and it always lies inside the triangle. The incenter is the intersection of the three angle bisectors. The product of the inradius and semiperimeter (half the perimeter) of a triangle is its area.

T=rs r=Ts=3594.18180.05=19.96T = rs \ \\ r = \dfrac{ T }{ s } = \dfrac{ 3594.18 }{ 180.05 } = 19.96

8. Circumradius

The circumcircle of a triangle is a circle that passes through all of the triangle's vertices, and the circumradius of a triangle is the radius of the triangle's circumcircle. Circumcenter (center of circumcircle) is the point where the perpendicular bisectors of a triangle intersect.

R=abc4 rs=100 90 170.094 19.963 180.046=106.48R = \dfrac{ a b c }{ 4 \ r s } = \dfrac{ 100 \cdot \ 90 \cdot \ 170.09 }{ 4 \cdot \ 19.963 \cdot \ 180.046 } = 106.48

9. Calculation of medians

A median of a triangle is a line segment joining a vertex to the midpoint of the opposite side. Every triangle has three medians, and they all intersect each other at the triangle's centroid. The centroid divides each median into parts in the ratio 2:1, with the centroid being twice as close to the midpoint of a side as it is to the opposite vertex. We use Apollonius's theorem to calculate the length of a median from the lengths of its side.

ma=2b2+2c2a22=2 902+2 170.09210022=126.552 mb=2c2+2a2b22=2 170.092+2 10029022=132.062 mc=2a2+2b2c22=2 1002+2 902170.0922=42.629m_a = \dfrac{ \sqrt{ 2b^2+2c^2 - a^2 } }{ 2 } = \dfrac{ \sqrt{ 2 \cdot \ 90^2+2 \cdot \ 170.09^2 - 100^2 } }{ 2 } = 126.552 \ \\ m_b = \dfrac{ \sqrt{ 2c^2+2a^2 - b^2 } }{ 2 } = \dfrac{ \sqrt{ 2 \cdot \ 170.09^2+2 \cdot \ 100^2 - 90^2 } }{ 2 } = 132.062 \ \\ m_c = \dfrac{ \sqrt{ 2a^2+2b^2 - c^2 } }{ 2 } = \dfrac{ \sqrt{ 2 \cdot \ 100^2+2 \cdot \ 90^2 - 170.09^2 } }{ 2 } = 42.629



#2 Obtuse scalene triangle.

Sides: a = 100   b = 90   c = 11.17704864286

Area: T = 236.0432577863
Perimeter: p = 201.1770486429
Semiperimeter: s = 100.5855243214

Angle ∠ A = α = 151.993323267° = 151°59'36″ = 2.65327823508 rad
Angle ∠ B = β = 25° = 0.4366332313 rad
Angle ∠ C = γ = 3.00767673296° = 3°24″ = 0.05224779897 rad

Height: ha = 4.72108515573
Height: hb = 5.24553906192
Height: hc = 42.26218261741

Median: ma = 40.15545748767
Median: mb = 55.11325202066
Median: mc = 94.96773894463

Inradius: r = 2.34766919234
Circumradius: R = 106.4799071242

Vertex coordinates: A[11.17704864286; 0] B[0; 0] C[90.63107787037; 42.26218261741]
Centroid: CG[33.93437550441; 14.08772753914]
Coordinates of the circumscribed circle: U[5.58552432143; 106.3322486432]
Coordinates of the inscribed circle: I[10.58552432143; 2.34766919234]

Exterior (or external, outer) angles of the triangle:
∠ A' = α' = 28.00767673296° = 28°24″ = 2.65327823508 rad
∠ B' = β' = 155° = 0.4366332313 rad
∠ C' = γ' = 176.993323267° = 176°59'36″ = 0.05224779897 rad

Calculate another triangle

How did we calculate this triangle?

The calculation of the triangle progress in two phases. The first phase is such that we try to calculate all three sides of the triangle from the input parameters. The first phase is different for the different triangles query entered. The second phase is the calculation of other characteristics of the triangle, such as angles, area, perimeter, heights, the center of gravity, circle radii, etc. Some input data also results in two to three correct triangle solutions (e.g., if the specified triangle area and two sides - typically resulting in both acute and obtuse) triangle).

1. Use the Law of Cosines

a=100 b=90 β=25  b2=a2+c22accosβ 902=1002+c22 100 c cos(25)  c2181.262c+1900=0  p=1;q=181.262;r=1900 D=q24pr=181.2622411900=25255.7521937 D>0  c1,2=q±D2p=181.26±25255.752 c1,2=90.6307787±79.460292275 c1=170.091070979 c2=11.1704864286   Factored form of the equation:  (c170.091070979)(c11.1704864286)=0   c>0a = 100 \ \\ b = 90 \ \\ β = 25^\circ \ \\ \ \\ b^2 = a^2 + c^2 - 2ac \cos β \ \\ 90^2 = 100^2 + c^2 -2 \cdot \ 100 \cdot \ c \cdot \ \cos (25^\circ ) \ \\ \ \\ c^2 -181.262c +1900 =0 \ \\ \ \\ p=1; q=-181.262; r=1900 \ \\ D = q^2 - 4pr = 181.262^2 - 4\cdot 1 \cdot 1900 = 25255.7521937 \ \\ D>0 \ \\ \ \\ c_{1,2} = \dfrac{ -q \pm \sqrt{ D } }{ 2p } = \dfrac{ 181.26 \pm \sqrt{ 25255.75 } }{ 2 } \ \\ c_{1,2} = 90.6307787 \pm 79.460292275 \ \\ c_{1} = 170.091070979 \ \\ c_{2} = 11.1704864286 \ \\ \ \\ \text{ Factored form of the equation: } \ \\ (c -170.091070979) (c -11.1704864286) = 0 \ \\ \ \\ \ \\ c>0

Now we know the lengths of all three sides of the triangle, and the triangle is uniquely determined. Next, we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a=100 b=90 c=11.17a = 100 \ \\ b = 90 \ \\ c = 11.17

2. The triangle perimeter is the sum of the lengths of its three sides

p=a+b+c=100+90+11.17=201.17p = a+b+c = 100+90+11.17 = 201.17

3. Semiperimeter of the triangle

The semiperimeter of the triangle is half its perimeter. The semiperimeter frequently appears in formulas for triangles that it is given a separate name. By the triangle inequality, the longest side length of a triangle is less than the semiperimeter.

s=p2=201.172=100.59s = \dfrac{ p }{ 2 } = \dfrac{ 201.17 }{ 2 } = 100.59

4. The triangle area using Heron's formula

Heron's formula gives the area of a triangle when the length of all three sides are known. There is no need to calculate angles or other distances in the triangle first. Heron's formula works equally well in all cases and types of triangles.

T=s(sa)(sb)(sc) T=100.59(100.59100)(100.5990)(100.5911.17) T=55716.1=236.04T = \sqrt{ s(s-a)(s-b)(s-c) } \ \\ T = \sqrt{ 100.59(100.59-100)(100.59-90)(100.59-11.17) } \ \\ T = \sqrt{ 55716.1 } = 236.04

5. Calculate the heights of the triangle from its area.

There are many ways to find the height of the triangle. The easiest way is from the area and base length. The area of a triangle is half of the product of the length of the base and the height. Every side of the triangle can be a base; there are three bases and three heights (altitudes). Triangle height is the perpendicular line segment from a vertex to a line containing the base.

T=aha2  ha=2 Ta=2 236.04100=4.72 hb=2 Tb=2 236.0490=5.25 hc=2 Tc=2 236.0411.17=42.26T = \dfrac{ a h _a }{ 2 } \ \\ \ \\ h _a = \dfrac{ 2 \ T }{ a } = \dfrac{ 2 \cdot \ 236.04 }{ 100 } = 4.72 \ \\ h _b = \dfrac{ 2 \ T }{ b } = \dfrac{ 2 \cdot \ 236.04 }{ 90 } = 5.25 \ \\ h _c = \dfrac{ 2 \ T }{ c } = \dfrac{ 2 \cdot \ 236.04 }{ 11.17 } = 42.26

6. Calculation of the inner angles of the triangle using a Law of Cosines

The Law of Cosines is useful for finding the angles of a triangle when we know all three sides. The cosine rule, also known as the law of cosines, relates all three sides of a triangle with an angle of a triangle. The Law of Cosines is the extrapolation of the Pythagorean theorem for any triangle. Pythagorean theorem works only in a right triangle. Pythagorean theorem is a special case of the Law of Cosines and can be derived from it because the cosine of 90° is 0. It is best to find the angle opposite the longest side first. With the Law of Cosines, there is also no problem with obtuse angles as with the Law of Sines, because cosine function is negative for obtuse angles, zero for right, and positive for acute angles. We also use inverse cosine called arccosine to determine the angle from cosine value.

a2=b2+c22bccosα  α=arccos(b2+c2a22bc)=arccos(902+11.17210022 90 11.17)=1515936"  b2=a2+c22accosβ β=arccos(a2+c2b22ac)=arccos(1002+11.1729022 100 11.17)=25 γ=180αβ=1801515936"25=324"a^2 = b^2+c^2 - 2bc \cos α \ \\ \ \\ α = \arccos(\dfrac{ b^2+c^2-a^2 }{ 2bc } ) = \arccos(\dfrac{ 90^2+11.17^2-100^2 }{ 2 \cdot \ 90 \cdot \ 11.17 } ) = 151^\circ 59'36" \ \\ \ \\ b^2 = a^2+c^2 - 2ac \cos β \ \\ β = \arccos(\dfrac{ a^2+c^2-b^2 }{ 2ac } ) = \arccos(\dfrac{ 100^2+11.17^2-90^2 }{ 2 \cdot \ 100 \cdot \ 11.17 } ) = 25^\circ \ \\ γ = 180^\circ - α - β = 180^\circ - 151^\circ 59'36" - 25^\circ = 3^\circ 24"

7. Inradius

An incircle of a triangle is a circle which is tangent to each side. An incircle center is called incenter and has a radius named inradius. All triangles have an incenter, and it always lies inside the triangle. The incenter is the intersection of the three angle bisectors. The product of the inradius and semiperimeter (half the perimeter) of a triangle is its area.

T=rs r=Ts=236.04100.59=2.35T = rs \ \\ r = \dfrac{ T }{ s } = \dfrac{ 236.04 }{ 100.59 } = 2.35

8. Circumradius

The circumcircle of a triangle is a circle that passes through all of the triangle's vertices, and the circumradius of a triangle is the radius of the triangle's circumcircle. Circumcenter (center of circumcircle) is the point where the perpendicular bisectors of a triangle intersect.

R=abc4 rs=100 90 11.174 2.347 100.585=106.48R = \dfrac{ a b c }{ 4 \ r s } = \dfrac{ 100 \cdot \ 90 \cdot \ 11.17 }{ 4 \cdot \ 2.347 \cdot \ 100.585 } = 106.48

9. Calculation of medians

A median of a triangle is a line segment joining a vertex to the midpoint of the opposite side. Every triangle has three medians, and they all intersect each other at the triangle's centroid. The centroid divides each median into parts in the ratio 2:1, with the centroid being twice as close to the midpoint of a side as it is to the opposite vertex. We use Apollonius's theorem to calculate the length of a median from the lengths of its side.

ma=2b2+2c2a22=2 902+2 11.17210022=40.155 mb=2c2+2a2b22=2 11.172+2 10029022=55.113 mc=2a2+2b2c22=2 1002+2 90211.1722=94.967m_a = \dfrac{ \sqrt{ 2b^2+2c^2 - a^2 } }{ 2 } = \dfrac{ \sqrt{ 2 \cdot \ 90^2+2 \cdot \ 11.17^2 - 100^2 } }{ 2 } = 40.155 \ \\ m_b = \dfrac{ \sqrt{ 2c^2+2a^2 - b^2 } }{ 2 } = \dfrac{ \sqrt{ 2 \cdot \ 11.17^2+2 \cdot \ 100^2 - 90^2 } }{ 2 } = 55.113 \ \\ m_c = \dfrac{ \sqrt{ 2a^2+2b^2 - c^2 } }{ 2 } = \dfrac{ \sqrt{ 2 \cdot \ 100^2+2 \cdot \ 90^2 - 11.17^2 } }{ 2 } = 94.967

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