0.5 0.5 0.5 triangle

Equilateral triangle.

Sides: a = 0.5   b = 0.5   c = 0.5

Area: T = 0.10882531755
Perimeter: p = 1.5
Semiperimeter: s = 0.75

Angle ∠ A = α = 60° = 1.04771975512 rad
Angle ∠ B = β = 60° = 1.04771975512 rad
Angle ∠ C = γ = 60° = 1.04771975512 rad

Height: ha = 0.43330127019
Height: hb = 0.43330127019
Height: hc = 0.43330127019

Median: ma = 0.43330127019
Median: mb = 0.43330127019
Median: mc = 0.43330127019

Inradius: r = 0.14443375673
Circumradius: R = 0.28986751346

Vertex coordinates: A[0.5; 0] B[0; 0] C[0.25; 0.43330127019]
Centroid: CG[0.25; 0.14443375673]
Coordinates of the circumscribed circle: U[0.25; 0.14443375673]
Coordinates of the inscribed circle: I[0.25; 0.14443375673]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 120° = 1.04771975512 rad
∠ B' = β' = 120° = 1.04771975512 rad
∠ C' = γ' = 120° = 1.04771975512 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     