Triangle calculator VC

Please enter the coordinates of the three vertices


Acute scalene triangle.

Sides: a = 8.06222577483   b = 7.07110678119   c = 6.70882039325

Area: T = 22.5
Perimeter: p = 21.84215294927
Semiperimeter: s = 10.92107647463

Angle ∠ A = α = 71.56550511771° = 71°33'54″ = 1.24990457724 rad
Angle ∠ B = β = 56.3109932474° = 56°18'36″ = 0.98327937232 rad
Angle ∠ C = γ = 52.12550163489° = 52°7'30″ = 0.91097531579 rad

Height: ha = 5.58215630565
Height: hb = 6.36439610307
Height: hc = 6.70882039325

Median: ma = 5.59901699437
Median: mb = 6.51992024052
Median: mc = 6.80107352544

Inradius: r = 2.06602952744
Circumradius: R = 4.2499182928

Vertex coordinates: A[-4; 0] B[-1; 6] C[3; -1]
Centroid: CG[-0.66766666667; 1.66766666667]
Coordinates of the circumscribed circle: U[0; 0]
Coordinates of the inscribed circle: I[1.3743530183; 2.06602952744]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 108.4354948823° = 108°26'6″ = 1.24990457724 rad
∠ B' = β' = 123.6990067526° = 123°41'24″ = 0.98327937232 rad
∠ C' = γ' = 127.8754983651° = 127°52'30″ = 0.91097531579 rad

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How did we calculate this triangle?

1. We compute side a from coordinates using the Pythagorean theorem

a = | beta gamma | = | beta - gamma | ; ; a**2 = ( beta _x- gamma _x)**2 + ( beta _y- gamma _y)**2 ; ; a = sqrt{ ( beta _x- gamma _x)**2 + ( beta _y- gamma _y)**2 } ; ; a = sqrt{ (-1-3)**2 + (6-(-1))**2 } ; ; a = sqrt{ 65 } = 8.06 ; ;

2. We compute side b from coordinates using the Pythagorean theorem

b = | alpha gamma | = | alpha - gamma | ; ; b**2 = ( alpha _x- gamma _x)**2 + ( alpha _y- gamma _y)**2 ; ; b = sqrt{ ( alpha _x- gamma _x)**2 + ( alpha _y- gamma _y)**2 } ; ; b = sqrt{ (-4-3)**2 + (0-(-1))**2 } ; ; b = sqrt{ 50 } = 7.07 ; ;

3. We compute side c from coordinates using the Pythagorean theorem

c = | alpha beta | = | alpha - beta | ; ; c**2 = ( alpha _x- beta _x)**2 + ( alpha _y- beta _y)**2 ; ; c = sqrt{ ( alpha _x- beta _x)**2 + ( alpha _y- beta _y)**2 } ; ; c = sqrt{ (-4-(-1))**2 + (0-6)**2 } ; ; c = sqrt{ 45 } = 6.71 ; ;


Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a = 8.06 ; ; b = 7.07 ; ; c = 6.71 ; ;

4. The triangle circumference is the sum of the lengths of its three sides

p = a+b+c = 8.06+7.07+6.71 = 21.84 ; ;

5. Semiperimeter of the triangle

s = fraction{ o }{ 2 } = fraction{ 21.84 }{ 2 } = 10.92 ; ;

6. The triangle area using Heron's formula

T = sqrt{ s(s-a)(s-b)(s-c) } ; ; T = sqrt{ 10.92 * (10.92-8.06)(10.92-7.07)(10.92-6.71) } ; ; T = sqrt{ 506.25 } = 22.5 ; ;

7. Calculate the heights of the triangle from its area.

T = fraction{ a h _a }{ 2 } ; ; h _a = fraction{ 2 T }{ a } = fraction{ 2 * 22.5 }{ 8.06 } = 5.58 ; ; h _b = fraction{ 2 T }{ b } = fraction{ 2 * 22.5 }{ 7.07 } = 6.36 ; ; h _c = fraction{ 2 T }{ c } = fraction{ 2 * 22.5 }{ 6.71 } = 6.71 ; ;

8. Calculation of the inner angles of the triangle using a Law of Cosines

a**2 = b**2+c**2 - 2bc cos( alpha ) ; ; alpha = arccos( fraction{ a**2-b**2-c**2 }{ 2bc } ) = arccos( fraction{ 8.06**2-7.07**2-6.71**2 }{ 2 * 7.07 * 6.71 } ) = 71° 33'54" ; ; beta = arccos( fraction{ b**2-a**2-c**2 }{ 2ac } ) = arccos( fraction{ 7.07**2-8.06**2-6.71**2 }{ 2 * 8.06 * 6.71 } ) = 56° 18'36" ; ; gamma = arccos( fraction{ c**2-a**2-b**2 }{ 2ba } ) = arccos( fraction{ 6.71**2-8.06**2-7.07**2 }{ 2 * 7.07 * 8.06 } ) = 52° 7'30" ; ;

9. Inradius

T = rs ; ; r = fraction{ T }{ s } = fraction{ 22.5 }{ 10.92 } = 2.06 ; ;

10. Circumradius

R = fraction{ a }{ 2 * sin( alpha ) } = fraction{ 8.06 }{ 2 * sin 71° 33'54" } = 4.25 ; ;




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