Triangle calculator VC

Please enter the coordinates of the three vertices


Right scalene triangle.

Sides: a = 8.06222577483   b = 4.4722135955   c = 6.70882039325

Area: T = 15
Perimeter: p = 19.24325976358
Semiperimeter: s = 9.62112988179

Angle ∠ A = α = 90° = 1.57107963268 rad
Angle ∠ B = β = 33.6990067526° = 33°41'24″ = 0.58880026035 rad
Angle ∠ C = γ = 56.3109932474° = 56°18'36″ = 0.98327937232 rad

Height: ha = 3.72110420377
Height: hb = 6.70882039325
Height: hc = 4.4722135955

Median: ma = 4.03111288741
Median: mb = 7.07110678119
Median: mc = 5.59901699437

Inradius: r = 1.55990410696
Circumradius: R = 4.03111288741

Vertex coordinates: A[-3; 1] B[3; 4] C[-1; -3]
Centroid: CG[-0.33333333333; 0.66766666667]
Coordinates of the circumscribed circle: U[0; 0]
Coordinates of the inscribed circle: I[2.33985616044; 1.55990410696]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 90° = 1.57107963268 rad
∠ B' = β' = 146.3109932474° = 146°18'36″ = 0.58880026035 rad
∠ C' = γ' = 123.6990067526° = 123°41'24″ = 0.98327937232 rad

Calculate another triangle




How did we calculate this triangle?

1. We compute side a from coordinates using the Pythagorean theorem

a = | beta gamma | = | beta - gamma | ; ; a**2 = ( beta _x- gamma _x)**2 + ( beta _y- gamma _y)**2 ; ; a = sqrt{ ( beta _x- gamma _x)**2 + ( beta _y- gamma _y)**2 } ; ; a = sqrt{ (3-(-1))**2 + (4-(-3))**2 } ; ; a = sqrt{ 65 } = 8.06 ; ;

2. We compute side b from coordinates using the Pythagorean theorem

b = | alpha gamma | = | alpha - gamma | ; ; b**2 = ( alpha _x- gamma _x)**2 + ( alpha _y- gamma _y)**2 ; ; b = sqrt{ ( alpha _x- gamma _x)**2 + ( alpha _y- gamma _y)**2 } ; ; b = sqrt{ (-3-(-1))**2 + (1-(-3))**2 } ; ; b = sqrt{ 20 } = 4.47 ; ;

3. We compute side c from coordinates using the Pythagorean theorem

c = | alpha beta | = | alpha - beta | ; ; c**2 = ( alpha _x- beta _x)**2 + ( alpha _y- beta _y)**2 ; ; c = sqrt{ ( alpha _x- beta _x)**2 + ( alpha _y- beta _y)**2 } ; ; c = sqrt{ (-3-3)**2 + (1-4)**2 } ; ; c = sqrt{ 45 } = 6.71 ; ;


Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS.

a = 8.06 ; ; b = 4.47 ; ; c = 6.71 ; ;

4. The triangle circumference is the sum of the lengths of its three sides

p = a+b+c = 8.06+4.47+6.71 = 19.24 ; ;

5. Semiperimeter of the triangle

s = fraction{ o }{ 2 } = fraction{ 19.24 }{ 2 } = 9.62 ; ;

6. The triangle area using Heron's formula

T = sqrt{ s(s-a)(s-b)(s-c) } ; ; T = sqrt{ 9.62 * (9.62-8.06)(9.62-4.47)(9.62-6.71) } ; ; T = sqrt{ 225 } = 15 ; ;

7. Calculate the heights of the triangle from its area.

T = fraction{ a h _a }{ 2 } ; ; h _a = fraction{ 2 T }{ a } = fraction{ 2 * 15 }{ 8.06 } = 3.72 ; ; h _b = fraction{ 2 T }{ b } = fraction{ 2 * 15 }{ 4.47 } = 6.71 ; ; h _c = fraction{ 2 T }{ c } = fraction{ 2 * 15 }{ 6.71 } = 4.47 ; ;

8. Calculation of the inner angles of the triangle using a Law of Cosines

a**2 = b**2+c**2 - 2bc cos( alpha ) ; ; alpha = arccos( fraction{ a**2-b**2-c**2 }{ 2bc } ) = arccos( fraction{ 8.06**2-4.47**2-6.71**2 }{ 2 * 4.47 * 6.71 } ) = 90° ; ; beta = arccos( fraction{ b**2-a**2-c**2 }{ 2ac } ) = arccos( fraction{ 4.47**2-8.06**2-6.71**2 }{ 2 * 8.06 * 6.71 } ) = 33° 41'24" ; ; gamma = arccos( fraction{ c**2-a**2-b**2 }{ 2ba } ) = arccos( fraction{ 6.71**2-8.06**2-4.47**2 }{ 2 * 4.47 * 8.06 } ) = 56° 18'36" ; ;

9. Inradius

T = rs ; ; r = fraction{ T }{ s } = fraction{ 15 }{ 9.62 } = 1.56 ; ;

10. Circumradius

R = fraction{ a }{ 2 * sin( alpha ) } = fraction{ 8.06 }{ 2 * sin 90° } = 4.03 ; ;




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