620 500 620 triangle

Acute isosceles triangle.

Sides: a = 620   b = 500   c = 620

Area: T = 141840.5879525
Perimeter: p = 1740
Semiperimeter: s = 870

Angle ∠ A = α = 66.22200052686° = 66°13'12″ = 1.15657571226 rad
Angle ∠ B = β = 47.56599894628° = 47°33'36″ = 0.83300784083 rad
Angle ∠ C = γ = 66.22200052686° = 66°13'12″ = 1.15657571226 rad

Height: ha = 457.5550256532
Height: hb = 567.36223181
Height: hc = 457.5550256532

Median: ma = 470.213271782
Median: mb = 567.36223181
Median: mc = 470.213271782

Inradius: r = 163.0355148879
Circumradius: R = 338.7610601239

Vertex coordinates: A[620; 0] B[0; 0] C[418.3877096774; 457.5550256532]
Centroid: CG[346.1299032258; 152.5176752177]
Coordinates of the circumscribed circle: U[310; 136.5977016629]
Coordinates of the inscribed circle: I[370; 163.0355148879]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 113.7879994731° = 113°46'48″ = 1.15657571226 rad
∠ B' = β' = 132.4440010537° = 132°26'24″ = 0.83300784083 rad
∠ C' = γ' = 113.7879994731° = 113°46'48″ = 1.15657571226 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     