6 24 24 triangle

Acute isosceles triangle.

Sides: a = 6   b = 24   c = 24

Area: T = 71.43552853987
Perimeter: p = 54
Semiperimeter: s = 27

Angle ∠ A = α = 14.36215115629° = 14°21'41″ = 0.25106556623 rad
Angle ∠ B = β = 82.81992442185° = 82°49'9″ = 1.44554684956 rad
Angle ∠ C = γ = 82.81992442185° = 82°49'9″ = 1.44554684956 rad

Height: ha = 23.81217617996
Height: hb = 5.95329404499
Height: hc = 5.95329404499

Median: ma = 23.81217617996
Median: mb = 12.72879220614
Median: mc = 12.72879220614

Vertex coordinates: A[24; 0] B[0; 0] C[0.75; 5.95329404499]
Centroid: CG[8.25; 1.98443134833]
Coordinates of the circumscribed circle: U[12; 1.5121857892]
Coordinates of the inscribed circle: I[3; 2.64657513111]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 165.6388488437° = 165°38'19″ = 0.25106556623 rad
∠ B' = β' = 97.18107557815° = 97°10'51″ = 1.44554684956 rad
∠ C' = γ' = 97.18107557815° = 97°10'51″ = 1.44554684956 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    