39.1 27.5 47.59 triangle

Acute scalene triangle.

Sides: a = 39.1   b = 27.5   c = 47.59

Area: T = 537.6011159699
Perimeter: p = 114.19
Semiperimeter: s = 57.095

Angle ∠ A = α = 55.2421738751° = 55°14'30″ = 0.96441502257 rad
Angle ∠ B = β = 35.29878406718° = 35°17'52″ = 0.61660635386 rad
Angle ∠ C = γ = 89.46604205772° = 89°27'38″ = 1.56113788893 rad

Height: ha = 27.49987805472
Height: hb = 39.09882661599
Height: hc = 22.59330304559

Median: ma = 33.59105723381
Median: mb = 41.32548901995
Median: mc = 24.00768318401

Inradius: r = 9.41659061161
Circumradius: R = 23.7966055206

Vertex coordinates: A[47.59; 0] B[0; 0] C[31.91218312671; 22.59330304559]
Centroid: CG[26.50106104224; 7.5311010152]
Coordinates of the circumscribed circle: U[23.795; 0.22440945503]
Coordinates of the inscribed circle: I[29.595; 9.41659061161]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 124.7588261249° = 124°45'30″ = 0.96441502257 rad
∠ B' = β' = 144.7022159328° = 144°42'8″ = 0.61660635386 rad
∠ C' = γ' = 90.54395794228° = 90°32'22″ = 1.56113788893 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     