25 29 29 triangle

Acute isosceles triangle.

Sides: a = 25   b = 29   c = 29

Area: T = 327.0976602703
Perimeter: p = 83
Semiperimeter: s = 41.5

Angle ∠ A = α = 51.06664578882° = 51°3'59″ = 0.89112778275 rad
Angle ∠ B = β = 64.46767710559° = 64°28' = 1.12551574131 rad
Angle ∠ C = γ = 64.46767710559° = 64°28' = 1.12551574131 rad

Height: ha = 26.16877282163
Height: hb = 22.55883863933
Height: hc = 22.55883863933

Median: ma = 26.16877282163
Median: mb = 22.86437267303
Median: mc = 22.86437267303

Vertex coordinates: A[29; 0] B[0; 0] C[10.7765862069; 22.55883863933]
Centroid: CG[13.25986206897; 7.51994621311]
Coordinates of the circumscribed circle: U[14.5; 6.92664705939]
Coordinates of the inscribed circle: I[12.5; 7.88218458483]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 128.9343542112° = 128°56'1″ = 0.89112778275 rad
∠ B' = β' = 115.5333228944° = 115°32' = 1.12551574131 rad
∠ C' = γ' = 115.5333228944° = 115°32' = 1.12551574131 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    