15 26 26 triangle

Acute isosceles triangle.

Sides: a = 15   b = 26   c = 26

Area: T = 186.7110839268
Perimeter: p = 67
Semiperimeter: s = 33.5

Angle ∠ A = α = 33.53217459453° = 33°31'54″ = 0.58552393707 rad
Angle ∠ B = β = 73.23441270273° = 73°14'3″ = 1.27881766415 rad
Angle ∠ C = γ = 73.23441270273° = 73°14'3″ = 1.27881766415 rad

Height: ha = 24.8954778569
Height: hb = 14.36223722514
Height: hc = 14.36223722514

Median: ma = 24.8954778569
Median: mb = 16.77879617356
Median: mc = 16.77879617356

Vertex coordinates: A[26; 0] B[0; 0] C[4.32769230769; 14.36223722514]
Centroid: CG[10.1098974359; 4.78774574171]
Coordinates of the circumscribed circle: U[13; 3.91664839217]
Coordinates of the inscribed circle: I[7.5; 5.57334578886]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 146.4688254055° = 146°28'6″ = 0.58552393707 rad
∠ B' = β' = 106.7665872973° = 106°45'57″ = 1.27881766415 rad
∠ C' = γ' = 106.7665872973° = 106°45'57″ = 1.27881766415 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    