14 28 29 triangle

Acute scalene triangle.

Sides: a = 14   b = 28   c = 29

Area: T = 192.8954887179
Perimeter: p = 71
Semiperimeter: s = 35.5

Angle ∠ A = α = 28.36765487929° = 28°22' = 0.49550896739 rad
Angle ∠ B = β = 71.84657453531° = 71°50'45″ = 1.254394481 rad
Angle ∠ C = γ = 79.7887705854° = 79°47'16″ = 1.39325581698 rad

Height: ha = 27.55664124542
Height: hb = 13.77882062271
Height: hc = 13.30330956676

Median: ma = 27.63215037593
Median: mb = 17.95882849961
Median: mc = 16.72657286837

Vertex coordinates: A[29; 0] B[0; 0] C[4.36220689655; 13.30330956676]
Centroid: CG[11.12106896552; 4.43443652225]
Coordinates of the circumscribed circle: U[14.5; 2.61221739532]
Coordinates of the inscribed circle: I[7.5; 5.43436587938]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 151.6333451207° = 151°38' = 0.49550896739 rad
∠ B' = β' = 108.1544254647° = 108°9'15″ = 1.254394481 rad
∠ C' = γ' = 100.2122294146° = 100°12'44″ = 1.39325581698 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    