1015 1035 1450 triangle

Obtuse scalene triangle.

Sides: a = 1015   b = 1035   c = 1450

Area: T = 525262.4344408
Perimeter: p = 3500
Semiperimeter: s = 1750

Angle ∠ A = α = 44.42769969877° = 44°25'37″ = 0.77553973742 rad
Angle ∠ B = β = 45.54443694382° = 45°32'40″ = 0.79548992024 rad
Angle ∠ C = γ = 90.02986335742° = 90°1'43″ = 1.57112960769 rad

Height: ha = 10354.99987075
Height: hb = 10154.99987325
Height: hc = 724.5499909528

Median: ma = 1152.955544146
Median: mb = 1139.542212296
Median: mc = 724.638784058

Inradius: r = 300.1549962519
Circumradius: R = 7255.000090535

Vertex coordinates: A[1450; 0] B[0; 0] C[710.8622068966; 724.5499909528]
Centroid: CG[720.2877356322; 241.5499969843]
Coordinates of the circumscribed circle: U[725; -0.36223188858]
Coordinates of the inscribed circle: I[715; 300.1549962519]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 135.5733003012° = 135°34'23″ = 0.77553973742 rad
∠ B' = β' = 134.4565630562° = 134°27'20″ = 0.79548992024 rad
∠ C' = γ' = 89.97113664258° = 89°58'17″ = 1.57112960769 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     