10 29 29 triangle

Acute isosceles triangle.

Sides: a = 10   b = 29   c = 29

Area: T = 142.8298568571
Perimeter: p = 68
Semiperimeter: s = 34

Angle ∠ A = α = 19.85663836846° = 19°51'23″ = 0.34765592728 rad
Angle ∠ B = β = 80.07218081577° = 80°4'19″ = 1.39875166904 rad
Angle ∠ C = γ = 80.07218081577° = 80°4'19″ = 1.39875166904 rad

Height: ha = 28.56657137142
Height: hb = 9.85502461083
Height: hc = 9.85502461083

Median: ma = 28.56657137142
Median: mb = 16.13222658049
Median: mc = 16.13222658049

Vertex coordinates: A[29; 0] B[0; 0] C[1.7244137931; 9.85502461083]
Centroid: CG[10.24113793103; 3.28334153694]
Coordinates of the circumscribed circle: U[14.5; 2.53880076523]
Coordinates of the inscribed circle: I[5; 4.20108402521]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 160.1443616315° = 160°8'37″ = 0.34765592728 rad
∠ B' = β' = 99.92881918423° = 99°55'41″ = 1.39875166904 rad
∠ C' = γ' = 99.92881918423° = 99°55'41″ = 1.39875166904 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    