10 25 30 triangle

Obtuse scalene triangle.

Sides: a = 10   b = 25   c = 30

Area: T = 117.094371247
Perimeter: p = 65
Semiperimeter: s = 32.5

Angle ∠ A = α = 18.19548723388° = 18°11'42″ = 0.31875604293 rad
Angle ∠ B = β = 51.31878125465° = 51°19'4″ = 0.89656647939 rad
Angle ∠ C = γ = 110.4877315115° = 110°29'14″ = 1.92883674304 rad

Height: ha = 23.4198742494
Height: hb = 9.36774969976
Height: hc = 7.8066247498

Median: ma = 27.1576951228
Median: mb = 18.54404962177
Median: mc = 11.72660393996

Vertex coordinates: A[30; 0] B[0; 0] C[6.25; 7.8066247498]
Centroid: CG[12.08333333333; 2.60220824993]
Coordinates of the circumscribed circle: U[15; -5.60444853832]
Coordinates of the inscribed circle: I[7.5; 3.60328834606]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 161.8055127661° = 161°48'18″ = 0.31875604293 rad
∠ B' = β' = 128.6822187453° = 128°40'56″ = 0.89656647939 rad
∠ C' = γ' = 69.51326848853° = 69°30'46″ = 1.92883674304 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    